As part of a study of the association between smoking and risk of squamous cell carcinoma, a logistic regression model was estim
ated as:
logit(probability of having squamous cell carcinoma) = -4.84 + 4.6*(SMOKER)
where SMOKER=0 for non-smoker and 1 for smoker. What is the predicted probability of a smoker having squamous cell carcinoma?
1 answer:
Answer:
0.44
Step-by-step explanation:
Given the estimated logistic regression model on risk of having squamous cell carcinoma
-4.84 + 4.6*(SMOKER)
SMOKER = 0 (non-smoker) ; 1 (SMOKER)
What is the predicted probability of a smoker having squamous cell carcinoma?
exp(-4.84 + 4.6*(SMOKER)) / 1 + exp(-4.84 + 4.6*(SMOKER))
SMOKER = 1
exp(-4.84 + 4.6) / 1 + exp(-4.84 + 4.6)
exp^(-0.24) / (1 + exp^(-0.24))
0.7866278 / 1.7866278
= 0.4402863
= 0.44
You might be interested in
Answer:
2 hours
Step-by-step explanation:
first tap= 3hours
therefore work done is = 1/3
second tap= 6hours
therefore work done = 1/6
so, 1/3+ 1/6
=2/6 + 1/6
=3/6
=1/2
=2/1 hours
=2 hours
Answer:
y = - 4x
Step-by-step explanation:
The slope-intercept form of a line is y = mx + b. In this case, m is - 4 and no b value is given.
Answer:
1/8 or 0.125
Step-by-step explanation:
hope this helped
Exception if the integer is a negative
Answer:
0.04409 quarter
Step-by-step explanation:
