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lesantik [10]
3 years ago
11

What is the midpoint of the segment that joins the points (-12, 12) and (-6, -1)?​

Mathematics
1 answer:
N76 [4]3 years ago
6 0

Answer:

\boxed {\boxed {\sf ( -9, \frac{11}{2}) }}

Step-by-step explanation:

We are asked to find the midpoint of a segment. We essentially calculate the average of the x-coordinates and the y-coordinates using the following formula.

( \frac {x_1+x_2}{2}, \frac{ y_1 + y_2}{2})

In this formula, (x₁ , y₁) and (x₂ , y₂) are the endpoints of the segment. For this problem, the 2 endpoints are (-12, 12) and (-6, -1). If we match the variable and the corresponding value, we see that:

  • x₁= -12
  • y₁= 12
  • x₂ = -6
  • y₂ = -1

Substitute the values into the formula.

( \frac{-12 + -6}{2}, \frac{12 + -1} {2} )

Solve the numerators.

  • -12 + -6 = -12 -6 = -18
  • 12 + -1 = 12-1 = 11

( \frac{-18}{2}, \frac{11}{2})

Divide.

( -9, \frac{11}{2} )

The midpoint of the segment is \bold {( -9, \frac{11}{2} )}.

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How do You supposed to do this i need many method to do it.
defon
I like the substitution method. Which is when you make one equation equal only x or y and plug it into the other equation)

There is also the graphing method. If you graphed it, it might not be quite as accurate (at least on hand, on computer you would be pretty exact)

Then there is the elimination method. You multiply one of the equations by a coefficient so that you can eliminate x or y from the equation. 
4 0
3 years ago
Pls help I don’t understand
dmitriy555 [2]

The answer is c. \frac{46}{9}

a. \frac{11}{5}=2.2 (2.2≠5.11) (2.2 is not equal to 5.11)

b. 5\frac{1}{8}=\frac{5}{8} or 0.625 (0.625≠5.11) (0.625 is not equal to 5.11)

c. \frac{46}{9} =5.11 (5.11=5.11) (5.11 is equal to 5.11)

Therefore c is the answer

4 0
3 years ago
Some steps to construct an angle MNT congruent to angle pqr
xxTIMURxx [149]
Maintaining the same width of the compass as AB, draw an arc from point X such that it intersects the afternoon drawn from N in a point
4 0
3 years ago
Solve using long division <br> Please
madreJ [45]

1. Solution,\frac{2x^3+4x^2-5}{x+3}:\quad 2x^2-2x+6-\frac{23}{x+3}

Steps:

\mathrm{Divide}\:\frac{2x^3+4x^2-5}{x+3}:\quad \frac{2x^3+4x^2-5}{x+3}=2x^2+\frac{-2x^2-5}{x+3}

\mathrm{Divide}\:\frac{-2x^2-5}{x+3}:\quad \frac{-2x^2-5}{x+3}=-2x+\frac{6x-5}{x+3}

\mathrm{Divide}\:\frac{6x-5}{x+3}:\quad \frac{6x-5}{x+3}=6+\frac{-23}{x+3}

\mathrm{Simplify}, =2x^2-2x+6-\frac{23}{x+3}

\mathrm{The\:Correct\:Answer\:is\:2x^2-2x+6-\frac{23}{x+3}}

2. Solution, \frac{4x^3-2x^2-3}{2x^2-1}:\quad 2x-1+\frac{2x-4}{2x^2-1}

Steps:

\mathrm{Divide}\:\frac{4x^3-2x^2-3}{2x^2-1}:\quad \frac{4x^3-2x^2-3}{2x^2-1}=2x+\frac{-2x^2+2x-3}{2x^2-1}

\mathrm{Divide}\:\frac{-2x^2+2x-3}{2x^2-1}:\quad \frac{-2x^2+2x-3}{2x^2-1}=-1+\frac{2x-4}{2x^2-1}

\mathrm{The\:Correct\:Answer\:is\:2x-1+\frac{2x-4}{2x^2-1}}

\mathrm{Hope\:This\:Helps!!!}

\mathrm{-Austint1414}

4 0
3 years ago
My sis needs help asap
Alika [10]

Answer:

3/4 - 5/12

Step-by-step explanation:

first you make the demoninators the same so 3*4=12

and if you *3 you do it to the numerator

so its 9/12-5/12

the unsimplified fraction is 4/12

if wanted simplified version its 1/3

3 0
2 years ago
Read 2 more answers
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