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il63 [147K]
3 years ago
6

A correct description of the line defined by y-6= -1/2(x+7) is

Mathematics
1 answer:
Helga [31]3 years ago
5 0

Answer:

C

Step-by-step explanation:

The correct answer is C

Because taking the point to be (a,b)

y - b = m(x - a)  \\ \: is \: the \:  \: equation \:  \: of \:  \: a \: line

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Pleaseeee help im confused best answer will get brainliest.
drek231 [11]

Answer:

The perimeter of the square would be 8x - 16.

Step-by-step explanation:

Since the sides of the square all the same, you can just multiply the length of one side by 4 to find the perimeter.  The perimeter is the distance around an object.  

4( 2x - 4 ) = 8x - 16

6 0
3 years ago
“If it is July then it is summer, and it is not July therefore it is not summer” Is this reasoning valid? Why or why not?
MAVERICK [17]

Answer:

No

Step-by-step explanation:

Summer starts in June and ends in August, so this is not valid.

Bam

6 0
3 years ago
Can someone help me? I’ll do anything
Temka [501]

To find x, we have to use the pythagorean theorem.

a^2 + b^2 = c^2.

In our problem,

a = 3

b = ?

c = 6.5

(3)^2 + b^2 = (6.5)^2

Simplify the left and right side.

9 + b^2 = 42.25.

Subtract 9 from each side

b^2 = 33.25.

Take the square root of each side

b = 5.8.

Multiply 5.8 by two becuase 5.8 is the radius and we are looking for the diameter

x = 11.6

8 0
3 years ago
Read 2 more answers
For the level 3 course, exam hours cost twice as much as workshop hours, workshop hours cost twice as much as lecture hours. How
natulia [17]
<h2>Answer</h2>

Cost of lectures = $7.33 per hour

<h2>Explanation</h2>

Let e the cost of the exam hours

Let w be the cost of the workshop hours

Let l be the cost of the lecture hours.

We know from our problem that exam hours cost twice as much as workshop, so:

e=2w equation (1)

We also know that workshop hours cost twice as much as lecture hours, so:

w=2l equation (2)

Finally, we also know that 3hr exams 24hr workshops  and 12hr lectures cost $528, so:

3e+24w+12l=528 equation (1)

Now, lets find the value of l:

Step 1.  Solve for l in equation (3)

3e+24w+12l=528

12l=528-3e-24w equation (4)

Step 2. Replace equation (1) in equation (4) and simplify

12l=528-3e-24w

12l=528-3(2w)-24w

12l=528-6w-24w

12l=528-30w equation (5)

Step 3. Replace equation (2) in equation (5) and solve for l

12l=528-30w

12l=528-30(2l)

12l=528-60l

72l=528

l=\frac{528}{72}

l=\frac{22}{3}

l=7.33

Cost of lectures  = $7.33 per hour



3 0
3 years ago
Read 2 more answers
Which strategies can be used to solve this problem?
Scorpion4ik [409]
B. and D. work. You are trying to figure out how many more cars they painted in the first and second years together than the third year. (5,000+7,213)-8,201=4,012
6 0
3 years ago
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