Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
Total no. of times owner-occupied units had a water supply stoppage lasting 6 or more hours
547000 + 5012000 + 6110000 + 2544000 + 557000 = 14770000
x = no. of times owner-occupied units had a water supply stoppage.
<h3>What is the probability at x =0?</h3>
P(x=0) = 547000/14770000
P(x=0) = 0.0370
Similarly, we have at x=1
P(x=1) = 5012000/14770000
P(x=1) = 0.3393
P(x=2) = 6110000/14770000
P(x=2) = 0.4137
P(x=3) = 2544000/14770000
P(x=3) = 0.1722
P(x=4) = 557000/14770000
P(x=4) = 0.0378
x f(x)
0 0.0370
1 0.3393
2 0.4137
3 0.1722
4 0.0378
Total 1
Observations can you make from a comparison of the number of water supply stoppages reported by owner-occupied units versus renter-occupied units 1.
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It’s in the Millions place
Answer:
x ≈ 33.0
Step-by-step explanation:
The third angle in the triangle is
180° - 70° - 76° = 180° - 146° = 34°
Using the Sine rule in the triangle
= 
( cross- multiply )
x × sin34° = 19 × sin76° ( divide both sides by sin34° )
x = 
≈ 33.0 ( to the nearest tenth )
Answer:
The equation for nth term is 3n + 5.
Step-by-step explanation:
Let a1 be a,
a3 = a + (n - 1)d
or, 14 = a + (3 - 1)d
so, 14 = a + 2d
Now,
a5 = a + (n - 1)d
or, 20 = a + (5 - 1)d
or, 20 = a + 4d
now,
a + 4d = 20
a + 2d = 14
now,
a + 4d - ( a + 2d) = 20 - 14
or, a + 4d - a - 2d = 6
or, 2d = 6
so, d = 3
Now,
a + 2d = 14
or, a + 2(3) = 14
or, a = 14 - 6
so, a = 8
Now,
an = a + (n - 1)d
or, an = 8 + (n - 1)3
or, an = 8 + 3n - 3
so, an = 3n + 5
The answer is 20.4285714285
