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ira [324]
3 years ago
12

Is hunter license a form of a tax

Mathematics
1 answer:
puteri [66]3 years ago
8 0
A hunting license is not a from of tax it is a form of license that allows you to hunt game and only costs each time for renewal of the right
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5 ft is ____ % of 37 1 2 ft; 37 1 2 ft is ____ % of 5 ft
hichkok12 [17]

Answer:

The answer is:

5 ft is <u>13.33</u>% of 37 1/2 ft; 37 1/2 ft is <u>750</u>% of 5 ft.

Step-by-step explanation:

Given:

5 ft is ____ % of 37 1 2 ft.

Now, to find the __ :

Let __ be x.

So, 5 ft is x\% of 37 1/2

5=x\% of 37\frac{1}{2}

⇒ 5=\frac{x}{100} \times \frac{75}{2}

⇒ 5=\frac{75x}{200}

Multiplying both sides by 200 we get:

⇒ 1000=75x

Dividing both sides by 75 we get:

⇒ 13.33=x

⇒ x=13.33\%.

Now, 37 1/2 ft is x% of 5 ft.

\frac{75}{2} =x\%\ of\ 5

\frac{75}{2}=\frac{x}{100}\times 5

\frac{75}{2} =\frac{5x}{100}

Multiplying both sides by 100 we get:

\frac{7500}{2} =5x

Dividing both sides by 5 we get:

750=x

x=750\%

Therefore, the answer is 5 ft is <u>13.33</u>% of 37 1/2 ft; 37 1/2 ft is <u>750</u>% of 5 ft.

8 0
3 years ago
Which ordered pair is a solution of the equation y = 10x?<br><br>​
ddd [48]

Answer:

THE ANSWER WILL BE...

NOTE : Just substitute the x and y variable with (-6,-60) and you will see I am right.

Example:

-60= 10(-6)

<em><u>Please mark as brainliest</u></em>

Have a great day, be safe and healthy

Thank u  

XD

6 0
3 years ago
If j ll k which could be one of the angle measures <br> A.25<br> B.37 <br> C.60<br> D.84
PtichkaEL [24]

Answer:

Hii friend

I am from India and u ??

Roshini here !!!!

3 0
2 years ago
Read 2 more answers
Help!<br> It's a picutre
9966 [12]

Here is your answer

a) 5x-2y= 1

REASON:

6-2(x-y)=3x+5

6-2x+2y= 3x+5

3x+2x-2y= 6-5

5x-2y= 1

HOPE IT IS USEFUL

3 0
3 years ago
Two random variables x and y are independent if the value of x does not affect the value of y. If the variables are not​ indepen
jeyben [28]

Answer: \mu_{x+y} = 3026

              \mu_{x-y}= 30

Step-by-step explanation: Average sum of the female and male's test score is the sum of expected value of each gender:

\mu_{x+y}=\mu_{x}+\mu_{y}

Assuming x represents the random male selected and y represents the random female selected:

\mu_{x+y}=1528+1498

\mu_{x+y}= 3026

The average sum of their scores is 3026.

Average difference is the difference between the expected value (mean) of each gender:

\mu_{x-y}=\mu_{x}-\mu_{y}

\mu_{x-y}= 1528 - 1498

\mu_{x-y}= 30

The average difference of their scores is 30.

6 0
3 years ago
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