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3 years ago

Is hunter license a form of a tax

1 answer:

8 0

A hunting license is not a from of tax it is a form of license that allows you to hunt game and only costs each time for renewal of the right

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Thank you for your help

olya-2409 [2.1K]

Answer:

I'm not completely sure but if they want exponents for 6 * 6 * 6 then it should be $6^{3}$

Step-by-step explanation:

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3 years ago

Solve the inequality k - 3 < 5

k0ka [10]

k-3+3<5+3 is the explanation and the answer is k<8

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3 years ago

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Complete the function table to find the function values of {-1, 7} for f(n) = 2n - 1.

allochka39001 [22]

Answer:

In its broadest definition, “civic education” means all the processes that ... That makes the question of good citizenship relative to the ... These questions are rarely treated together as part of comprehensive theories of civic education; ... of virtue, so would the polis itself become more virtuous and excellent.

Step-by-step explanation:

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3 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that $\pi = 0.2$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}$

$0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}$

$\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}$

$(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}$

$n = 5615$

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now $\pi = 0.12, n = 5615$ .

We have to find M.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 2.81\sqrt{\frac{0.12*0.88}{5615}}$

$M = 0.012$

7 0

3 years ago

Which ordered pair describes point P? A) -2, +4 B) -2, -4 C) +4, -2 D) -4, -2

zimovet [89]

The answer is a. (-2, 4). The horizontal line is the x-axis, and the vertical line is the y-axis, so the coordinate points would be (x, y) and (-2, 4) fit those coordinates. Hope this helps! :)

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3 years ago

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