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aliya0001 [1]
2 years ago
13

What is the name of the shapes A,B,D

Mathematics
1 answer:
artcher [175]2 years ago
4 0

Answer:

i believe the bottom is a <em>irregular quadrilateral </em>and the first one is a <em>parallelogram </em>

Step-by-step explanation:

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Greatest common factor of 15 and 33
Rashid [163]
15 = 3 x 5
33 = 3 x 11
so
GCF = 3
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Can you help me I forgot
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Harrison walked a total of 14 km because the first rectangle has a perimeter of 6 km and the second has a perimeter of 8 km. Harrison’s brother walked a total of 12 km since that was the perimeter of the 5*1. 14-12 is 2 so there is a 2 km difference.
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usain bolt, a Jamaica retired sprinter and world record holder in the 100 meters, 200 meters and 4 × 100 meters relay, has an av
Novosadov [1.4K]

For this case we have the following conversion of units:

1mi = 1609m

1h = 3600s

Thus, applying the conversion of units we have:

(23.35 \frac{mi}{h}) (\frac{1609}{1}\frac{m}{mi}) (\frac {1}{3600}\frac{h}{s}) = 10.4 \frac{m}{s}

Then, the distance traveled for 5 seconds is given by:

d = (10.4) (5)

d = 52m

Answer:

he has completed 52 meters of the 80-meter race

5 0
3 years ago
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
6x-7y= -2 please help me
Nana76 [90]

Answer:

X=7/6y+-1/3

Step-by-step explanation:

It will be hard for me to demonstrate the equation

6 0
3 years ago
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