Answer:
<h2><em>
2(3s-14)</em></h2>
Step-by-step explanation:
Given the angles ∠ABF=8s-6, ∠ABE = 2(s + 11), we are to find the angle ∠EBF. The following expression is true for the three angles;
∠ABF = ∠ABE + ∠EBF
Substituting the given angles into the equation to get the unknown;
8s-6 = 2(s + 11)+ ∠EBF
open the parenthesis
8s-6 = 2s + 22+ ∠EBF
∠EBF = 8s-6-2s-22
collect the like terms
∠EBF = 8s-2s-22-6
∠EBF = 6s-28
factor out the common multiple
∠EBF = 2(3s-14)
<em></em>
<em>Hence the measure of angle ∠EBF is 2(3s-14)</em>
Answer:
Step-by-step explanation:
I hope this helps
Answer:
The answer is...
Step-by-step explanation:
Cost
Answer:
8 units
Step-by-step explanation:
so there is something called Pythagorean thereon and it states that a^2+b^2=c^2
and 6 is either a or b
and c is ten so
6^2+b^2=10^2
36+b^2=100
b^2=64
here you need to find the square root in order to delete the power so
b=8
or
x=8
Answer:
Obtuse triangle.
Step-by-step explanation:
Side a = 5
Side b = 2
Side c = 4
Angle ∠A = 108.21° = 108°12'36" = 1.88862 rad
Angle ∠B = 22.332° = 22°19'54" = 0.38976 rad
Angle ∠C = 49.458° = 49°27'30" = 0.86321 rad
Since one angle is above 90 degrees, the triangle is obtuse triangle.
This cannot be an acute triangle.
