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frutty [35]
3 years ago
7

An object is dropped off a building that is 144 feet tall. After how many seconds does the object hit the ground? (d=16t^2)

Mathematics
1 answer:
andrew-mc [135]3 years ago
7 0

Answer:

after 3 seconds, the object hits the ground.

Hope this helps :)

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Find the volume of this sphere.<br> Use 3 for TT.<br> V [?]in3<br> V = Tr3<br> 8 in
frutty [35]

Answer:

The volume of the sphere is 2048 in³.

Step-by-step explanation:

The volume of a sphere is given by:

V = \frac{4}{3}\pi r^{3}

Where:

r: is the radius = 8 in

Having the radius and by using 3 for π, the volume is:

V = \frac{4}{3}*3 (8 in)^{3} = 2048 in^{3}

Therefore, the volume of the sphere is 2048 in³.

I hope it helps you!        

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3 years ago
(15x-24x+9) divided by(3x-3)
Thepotemich [5.8K]
I belive this is -3x+3/x^3
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3 years ago
HELP Combining like terms solve all please :) c
In-s [12.5K]

Answer:

11. x = -16

12. k = 6

13. x = -19

14. x = -6

15. x = -20

16. Combining like terms isn't to be used on this type of problem. I'm sorry, can you guess on this one?

17. x = 19

18. n = -10

19. b = 11

20. n = 4

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2 years ago
17. Two tanks are similar in shape. The capacity of the tanks are 1,000,000 litres and 512, 000 liters respectively
Gnesinka [82]

Given that, Two tanks are similar in shape. The capacity of the tanks are 1,000,000 litres and 512, 000 liters respectively.Find the height of the smallest tank if the larger is 300cm tall?

Assume that, the tanks are rectangular in shapes and differ only on their heights. The volume of the larger tank is

V1 = l × w × h1 while the volume of the smaller tank is V2 = l ×w × h2. The ratios of the capacities is

\sf \frac{V1}{V2} = l  \times  w  \times h1  \times  w  \times  h2 =  \frac{h1}{h2}

Solving for the height of the smaller tank h2

\sf \frac{V1}{V2} =  \frac{h1}{h2}

\sf\frac{1000000} {51200} = \frac{ 300 cm }{ h2}

1000000 × h2 = 51200 × 300 cm

h2 = (51200 × 300 cm) /1000000

h2 = 15.36 cm

\sf\implies \: \boxed{ \bf{ \: Height \:  of  \: the \:  smaller  \: tank  \: is  \: 15.36 cm.\: }}

{ \underline {\rule{5000pt}{6pt}}}

5 0
2 years ago
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