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3 years ago

What is the product of x and y

1 answer:

6 0

I think it would be (8)(-1) = -8. by adding the two equations you get 2x = 16 so x = 8 then y = 7 - x = -1. Therefore xy = -8.

Hope that helps

You might be interested in

A rumor spreads through a small town. Let y ( t ) be the fraction of the population that has heard the rumor at time t and assum

Ivan

Answer:

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solution

$y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

The rumor reaches 80% at 8.48 days.

Step-by-step explanation:

We know

y(t): proportion of people that heard the rumor

y'(t)=ky(1-y), rate of spread of the rumor

Differential equation

$\frac{dy}{dt} =ky(1-y)$

Solving the differential equation

$\frac{dy}{y(1-y)}=k\cdot dt \\\\\int \frac{dx}{y(1-y)} =k \int dt \\\\-ln(1-\frac{1}{y} )+C_0=kt\\\\1-\frac{1}{y} =Ce^{-kt}\\\\\frac{1}{y} =1-Ce^{-kt}\\\\y=\frac{1}{1-Ce^{-kt}}$

Initial conditions:

$y(0)=0.2\\y(3)=0.4\\\\y(0)=0.2=\frac{1}{1-Ce^0}\\\\1-C=1/0.2\\\\C=1-1/0.2= -4\\\\\\y(3)=0.4=\frac{1}{1+4e^{-3k}} \\\\1+4e^{-3k}=1/0.4\\\\e^{-3k}=(2.5-1)/4=0.375\\\\k=ln(0.375)/(-3)=0.327\\\\\\y=\frac{1}{1+4e^{-0.327t}}$

Value of constant k=0.327 days^(-1)

At what time the rumor reaches 80%?

$y(t)=0.8=\frac{1}{1+4e^{-0.327t}} \\\\1+4e^{-0.327t}=1/0.8=1.25\\\\e^{-0.327t}=(1.25-1)/4=0.0625\\\\t=ln(0.0625)/(-0.327)=8.48$

The rumor reaches 80% at 8.48 days.

8 0

3 years ago

Put in least to highest order 6.86,6.8,7,6.9,6.827 and 12.03,1.2,12.3,1.203,12.301

Anon25 [30]

6.8,6.827,6.86,6.9

1.2,1.203,12.03, 12.301,12.31

6 0

2 years ago

Im really bad at the functions stuff so- yk help

atroni [7]

Answer:Isolate the variable by dividing each side by factors that don't contain the variable.

w =-3u/2+2

4 0

2 years ago

What is the value of P for the following triangular prism?

Zolol [24]

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3 0

2 years ago

Anyone know the answer to this geometry problem?

hoa [83]

Let's talk about the choices
◯  ∠4 and ∠5 . . . . . . . . these are complementary angles whose sum is 90°
◯  ∠7 and ∠9 . . . . . . . . these are vertical angles, equal to each other
◯  ∠2 and ∠3 . . . . . . . . these are supplementary angles that together form a straight line. They are a linear pair.
◯  ∠1 and ∠2 . . . . . . . . these are "adjacent" angles in the quadrilateral that also includes ∠9 and ∠10.

The appropriate choice is ...
◉ ∠2 and ∠3

7 0

3 years ago