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ioda
2 years ago
15

Where can i find the answers?

Mathematics
1 answer:
Reil [10]2 years ago
5 0

Answer:

I don't know where can you find this question's answer.

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Find an expression equivalent to the one shown below.
TEA [102]

Answer:

  C)  1/6^32

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)^c = a^(b·c)

  (a^b)(a^c) = a^(b+c)

  a^-b = 1/a^b

_____

Using these rules, your expression simplifies to ...

  6^8·6^(10(-4)) = 6^8·6^-40 = 6^(8-40) = 6^-32 = 1/6^32

6 0
3 years ago
What is the product of <br><br> 2x+3 and 4x^2-5x+6 .
stira [4]

Answer:

Explanation:

We have:

(

2

x

+

3

)

(

4

x

2

−

5

x

+

6

)

Now let's distribute this piece by piece:

(

2

x

)

(

4

x

2

)

=

8

x

3

(

2

x

)

(

−

5

x

)

=

−

10

x

2

(

2

x

)

(

6

)

=

12

x

(

3

)

(

4

x

2

)

=

12

x

2

(

3

)

(

−

5

x

)

=

−

15

x

(

3

)

(

6

)

=

18

And now we add them all up (I'm going to group terms in the adding):

8

x

3

−

10

x

2

+

12

x

2

+

12

x

−

15

x

+

18

And now simplify:

8

x

3

+

2

x

2

−

3

x

+

18Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A discuss moves from P1 (4,8) to P2 (15,17). What is the lincar displacement in the horizontal and vertical directions? What is
Yakvenalex [24]

Answer:

The horizontal displacement is 11 units, the vertical displacement is 9 units, and the projection angle is 39.3 degrees.

Step-by-step explanation:

We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

Once we have found them, we can use trigonometric functions to find the projection angle with respect the horizontal.

Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

So we can use the given points P1:(x_1,y_2)  \text{  and  } P_2: (x_2,y_2) on the displacement formula

\Delta x = 15-4\\\Delta x = 11

In the same manner we can look at the y components of those points to find the vertical displacement

\Delta y = 17-8\\\Delta y =9

Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

7 0
3 years ago
ABCD is a rhombus, where m∠AED = 5x – 10. Use the properties of a rhombus to determine the value of x. Question 10 options: A) x
fomenos

Answer:

A) x = 20

Step-by-step explanation:

ABCD is a rhombus, AC and BD are diagonals which intersect each other at point E.

Since, diagonals of a rhombus are perpendicular bisector.

\therefore \: m \angle AED = 90 \degree \\  \therefore \: (5x - 10) \degree = 90 \degree \\ \therefore \: 5x - 10 = 90  \\ \therefore \: 5x  = 90 + 10  \\ \therefore \: 5x  = 100  \\ \\  \therefore \: x  = \frac{100}{5}  \\  \\ \huge \red{ \boxed{ \therefore \: x  =20}}

5 0
3 years ago
Simplify please <br> (n^11)^2
Citrus2011 [14]

Answer:

n^22 (I love your profile picture by the way)

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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