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2 years ago

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Mathematics

1 answer:

Reil [10]2 years ago

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Answer:

I don't know where can you find this question's answer.

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Alfonso bought 1/2 pound of raisins, 2/5 pound of walnuts, and 1/3 pound of almonds. Write a comparison statement comparing the

elixir [45]

2/5 lbs walnuts > 1/3 lbs almonds
Hope this helped ;)

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3 years ago

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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ICE Princess25 [194]

Answer:

Part a) The area of the figure is $\frac{9}{2}(4+\pi )\ cm^{2}$

Part b) The perimeter of the figure is $3(2+2\sqrt{2}+ \pi)\ cm$

Step-by-step explanation:

Step 1

Find the area of the figure

In this problem we have that

The figure ABC is the half of a square and the other figure is a semicircle

<u>Find the area of the figure ABC</u>

we have

$AB=6\ cm, BC=6\ cm$

The area of the half square ABC is equal to find the area of triangle ABC

$A1=\frac{1}{2}*6*6=18\ cm^{2}$

<u>Find the area of the semicircle</u>

The area of the semicircle is equal to

$A2=\pi r^{2}/2$

we have that

$r=6/2=3\ cm$

substitute

$A2=\pi (3)^{2}/2$

$A2=(9/2) \pi\ cm^{2}$

The area of the figure is equal to

$18\ cm^{2}+(9/2) \pi\ cm^{2}= \frac{9}{2}(4+\pi )\ cm^{2}$

Step 2

Find the perimeter of the figure

The perimeter of the figure is equal to

$P=AB+AC+length\ CB$

we have

$AB=6\ cm$

Applying Pythagoras theorem

$AC=\sqrt{6^{2}+6^{2}}\\AC=6\sqrt{2}\ cm$

Remember that

the circumference of a semicircle is equal to

$C=\frac{1}{2}2\pi r=\pi r$

$r=6/2=3\ cm$

$C=\pi(3)$

$C=3 \pi\ cm$

The perimeter of the figure is equal to

$P=6\ cm+6\sqrt{2}\ cm+3 \pi\ cm$

Simplify

$P=3(2+2\sqrt{2}+ \pi)\ cm$

5 0

3 years ago

The copy machine takes 3 hours to make 24 copies of an information packet. How long would it take to make 96 copies?

kompoz [17]

It would take 12 hours

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2 years ago

Describe how the graph of y= 1/3x is the same and different from the graph of y= 1/3x - 4

uranmaximum [27]

Answer:

the lines have the same slope

the y-intercept of the lines are different

Step-by-step explanation:

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3 years ago

The front yard of a house is 80 feet long and 50 feet wide. The backyard of the house is 50 feet long and 40 feet wide. What is

Alisiya [41]

Simple, the area is 80*50, 80*50=4,000 ft², the backyard has a dimension of 50*40=2,000 ft², subtract 4,000 from 2,000, 4,000-2,000=2,000 ft²

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3 years ago

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