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3 years ago

12

1/3 of the quantity6.5 and p

1 answer:

andrey2020 [161]3 years ago

5 0

(6.5 + p)/3

or

1/3(6.5 + p)

same answer written a different way

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Jenna goes for a jog every morning. The line plot shows the number of hours she jog for 5 days how many total hours did she draw

vichka [17]

You need to show the line put. If you show the line plot i may be able to answer. But F.Y.I. you are going to probably using proportions or need to multiply the hours she jogs in one day by the 5 days. Hope this helps.

8 0

3 years ago

Two-thirds had their picture taken. If 124 had their picture taken, how many total?

krok68 [10]

Answer:

93

Step-by-step explanation:

if you do 124* $\frac{3}{4}$

6 0

3 years ago

Read 2 more answers

Which of the following equations could be th equation to represent the given graph? Make sure you explain your answer thoroughly

Alex17521 [72]

Answer:

Option (C) is correct.

Step-by-step explanation:

The given options of the possible equation for the graph are as follows:

$(A) y=2\left(\frac{3}{2}\right)^x \\\\(B) y=-2\left(\frac{3}{2}\right)^{-x} \\\\(C) y=2\left(\frac{2}{3}\right)^x \\\\(D) y=-2\left(\frac{2}{3}\right)^{-x} \\\\$

The given graph is decreasing and at x=0, y=2.

So, first checking the value of the given options for x=0

$(A) y=2\left(\frac{3}{2}\right)^0=2\times 1= 2 \\\\(B) y=--2\left(\frac{3}{2}\right)^{-0}= -2\times 1= -2 \; (not\; possible) \\\\(C) y=2\left(\frac{2}{3}\right)^0= 2\times 1= 2 \\\\(D) y=2\left(\frac{2}{3}\right)^{-0} = -2\times 1= -2 \; (not\; possible)$

As, for x=0, y=2, so options (C) and (D) are not possible, so rejected.

Now, checking the nature (increasing or decreasing) of the given equation by differentiating it.

For option (A),

$\frac{dy}{dx}=2\left(\frac{3}{2}\right)^{x}\times \ln\left(\frac{3}{2}\right)$

As $\ln \left(\frac{3}{2}\right)=\ln(1.5)>0 \;and\; \left(\frac{3}{2}\right)^{x} >0$

So, $\frac{dy}{dx}>0$

Therefore, the function in option (A) is increasing function.

Similarly, for option (C),

$\frac{dy}{dx}=2\left(\frac{2}{3}\right)^{x}\times \ln\left(\frac{2}{3}\right)$

As $\ln \left(\frac{2}{3}\right)=\ln(0.67)0$

So, $\frac{dy}{dx}$

Therefore, the function in option (C) is decreasing function.

As the given graph is decreasing, so, (C) represents $y=2\left(\frac{2}{3}\right)^x$ the given graph.

Hence, option (C) is correct.

6 0

3 years ago

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 49.049.0 and

sveta [45]

Answer:

10% probability that a given class period runs between 51.25 and 51.75 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability of finding a value X between c and d, d greater than c, is given by the following formula:

$P(c \leq X \leq d) = \frac{d-c}{b-a}$

Uniformly distributed between 49 and 54 minutes

This means that $b = 54, a = 49$

Find the probability that a given class period runs between 51.25 and 51.75 minutes.

$P(51.25 \leq X \leq 51.75) = \frac{51.75 - 51.25}{54 - 49} = 0.1$

10% probability that a given class period runs between 51.25 and 51.75 minutes.

6 0

3 years ago

William bought a new pair of shorts at the store when they were having a 50% off sale.

aliina [53]

William payed $15 bucks

5 0

3 years ago