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3 years ago

Solve thefollowinga) 2(x + 3) = x - 4

Mathematics

2 answers:

Georgia [21]3 years ago

7 0

Answer:

x = -10

Step-by-step explanation:

2(x + 3) = x - 4

2x + 6 = x - 4

2x - x = -4 - 6

x = -10

Doss [256]3 years ago

7 0

The answer is x=10 this is most definitely the correct answer

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Does (3,6) make the inequality 4x+y >19 true

mrs_skeptik [129]

(3,6)
4x + y > 19

4(3) + 6 > 19
12 + 6 > 19
18 > 19

No

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4 years ago

−22−(−32)−62+54+26+(−41)

murzikaleks [220]

Negative 22 minus negative 32 = 10

10 minus 62 = -52

-52 + 54 = 2

2 plus 26 = 28

28 minus 41 = -13

-13 is the answer

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3 years ago

Find the value of x in the isosceles triangle shown below.

Feliz [49]

Answer:

x = 6

Step-by-step explanation:

The isosceles triangle is divided into two forming two right triangles

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x^2 + 4^2 = 52

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3 years ago

What is the exact number for pi?

Inessa05 [86]

Answer:

3.14

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Step-by-step explanation:

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3 years ago

Read 2 more answers

The difference of two trinomials is x2 - 10x + 2. If one of the trinomials is 3x? - 11x - 4, then which expression could be the

klio [65]

Answer:

$2x^2-x-6$

$4x^2-21x-2$

Step-by-step explanation:

The difference of two trinomials $P(x)$ and $Q(x)$ is $x^2 - 10x + 2.$ This means that

$P(x)-Q(x)=x^2-10x+2$

$Q(x)-P(x)=x^2-10x+2$

If one of the trinomials is $P(x)=3x^2-11x - 4,$ then

$(3x^2-11x-4)-Q(x)=x^2-10x+2$

$Q(x)-(3x^2-11x-4)=x^2-10x+2$

1. If $(3x^2-11x-4)-Q(x)=x^2-10x+2,$ then

$Q(x)=(3x^2-11x-4)-(x^2-10x+2)\\ \\Q(x)=(3x^2-x^2)+(-11x+10x)+(-4-2)\\ \\Q(x)=2x^2-x-6$

2. If $Q(x)-(3x^2-11x-4)=x^2-10x+2,$ then

$Q(x)=(x^2-10x+2)+(3x^2-11x-4)\\ \\Q(x)=(x^2+3x^2)+(-10x-11x)+(2-4)\\ \\Q(x)=4x^2-21x-2$

4 0

3 years ago

Solve thefollowinga) 2(x + 3) = x - 4​

Solve thefollowinga) 2(x + 3) = x - 4