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Luba_88 [7]
3 years ago
10

1) 25 - p + 5 please help

Mathematics
2 answers:
andreev551 [17]3 years ago
8 0

Answer:

25-p+5

= -p+25+5

= -p+30

-p+30 it is

Step-by-step explanation:

hope that helps>3

amm18123 years ago
4 0
P=30

25-p+5
+p +p
______
p=25+5
p=30
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The amount of a chemical solution is measured to be 2 liters. What is the percent error of the measurement?
dezoksy [38]
The complete question in the attached figure

we know that
2 liters may be 1.5 to 1.9 rounded up to 2
or 2.1 to 2.4 rounded down to 2

the biggest percent error would be between 2 and 1.5, which is a volume error of 0.5 liters
2 - 1.5 = 0.5 liters
percent error = (absolute error / quantity) * 100
percent error = [0.5/2] * 100% = 0.25 * 100% = 25%

the answer is the option C) 25%

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vivado [14]
She'll have 17 with a remainder, just divide 139 by 8.
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3 years ago
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Line m passes through the points (5, 1) and (8, 6) while line n passes through the points (-4, 3) and (-1, 8). Which statement a
Anna [14]
Find the equations of the lines...

First find the slope...(y2-y1)/(x2-x1)=m

m=(6-1)/(8-5)=5/3 and it passes through (5,1) so

y=mx+b becomes:

y=5x/3+b and using (5,1)

1=5(5)/3+b

1=25/3+b

3/3-25/3=b

b=-22/3 so 

y1=(5x-22)/3

.... now y2...

m=(8-3)/(-1--4)=5/3 (note it has the same slope as y1...

y=5x/3+b and using the point (-1,8)

8=5(-1)/3+b

8=-5/3+b

24/3+5/3=b

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y2=(5x+29)/3

Since these lines have the same slope but different y-intercepts, they are parallel to each other. (and will never intersect.)
8 0
3 years ago
Two lighthouses are located 60 miles from one another on a north-south line. If a boat is spotted S 21o E from the northern ligh
jasenka [17]

Answer:

(A)The northern lighthouse is 8.2 miles closer than the southern lighthouse.

Step-by-step explanation:

The triangle attached represents the given problem.

First, let us determine the distance of the Boat from each of the lighthouse.

In Triangle ABC,

∠A+∠B+∠C=180 degrees

21+∠B+16=180

∠B=180-37=143 degrees.

Using Law of Sines

\frac{a}{Sin A}=\frac{b}{Sin B}\\\frac{a}{Sin 21^0}=\frac{60}{Sin 143^0} \\\text{Cross Multiply}\\a*sin143=60*sin21\\a=60*sin21\div sin143\\a=35.73 miles

Similarly

\frac{c}{Sin C}=\frac{b}{Sin B}\\\frac{c}{Sin 16^0}=\frac{60}{Sin 143^0} \\\text{Cross Multiply}\\c*sin143=60*sin16\\c=60*sin16\div sin143\\c=27.48 miles

Difference in Distance =35.73-27.48=8.25 miles

Therefore, the northern lighthouse is 8.2 miles closer than the southern lighthouse.

8 0
4 years ago
I am a number greater than 40,000 and less than 60,000. My ones digit and tens digit are the same. My ten-thousands digit is 1 l
jarptica [38.1K]
I am a number greater than 40,000 and less than 60,000:

40,000 < n < 60,000

This means that:

n = 10,000n₁ + 1,000n₂ + 100n₃ + 11n₄

And also:

4 ≤ n₁ < 6

0 ≤ n₂ ≤ 9

0 ≤ n₃ ≤ 9

0 ≤ n₄ ≤ 9

My ten thousands digit is 1 less than 3 times the sum of my ones digit and tens digit:

n₁ = 3*2n₄ - 1

n₁ = 6n₄ - 1

This means that:

n = 10,000*(6n₄-1) + 1,000n₂ + 100n₃ + 11n₄

n = 60,000n₄ - 10,000 + 1,000n₂ + 100n₃ + 11n₄

n = 60,011n₄ - 10,000 + 1,000n₂ + 100n₃

<span>My thousands digit is half my hundreds digit, and the sum of those two digits is 9:

n</span>₂ = 1/2 * n₃
<span>
n</span>₂ + n₃ = 9
<span>
Therefore:

n</span>₂ = 9 - n₃
<span>
Therefore:

9 - n</span>₃ = 1/2 * n₃
<span>
9 = 1/2 * n</span>₃ + n₃
<span>
9 = 1.5 * n</span>₃
<span>
Therefore:

n</span>₃ = 6
<span>
If n</span>₃=6, n₂=3.
<span>
This means that:

</span>n = 60,011n₄ - 10,000 + 1,000*3 + 100*6

n = 60,011n₄ - 10,000 + 3,000 + 600

n = 60,011n₄ - 6,400

Therefore:

0<n₄<2, so n₄=1.

If n₄=1:

n = 60,011 - 6,400

n = 53,611

Answer:

53,611
3 0
3 years ago
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