Answer:
so here correct option is A. 5
Explanation:
solution
as number of population groups live in a definite area is called diversity
so here in 1 there is only 2 groups of population
and in 2 there is 3 types of population groups
and in 3 there is 2 type of population groups
and in 4 there is 4 type population group
but they are not not evenly abundant and population of 1 group that is much less
so it might be a foreign population group
so here in 5 there is 4 type of population group which means it has higher diversity compare to other
so here correct option is A. 5
The correct answer is: Artificial selection (selective breeding).
Artificial Selection is a form of selection, totally influenced by human, in which traits that should be passed onto offspring are chosen by human. Selective breeding was used long before the genetics was discoverd. Farmers used individuals with beneficial traits, larger in size, with bigger fruit etc.
Hunting is also one type of selective breeding, since the hunters choose the animal and remove it from the population (gene pool), leaving the “weaker” to pass on to the next generation.
Answer:
Enzyme inhibitors may alter the elimination rate of a particular drug or inhibit detoxication pathways
Explanation:
An enzyme inhibitor is a chemical compound capable of binding to an enzyme in order to reduce its activity. An enzyme inhibitor may bind to an active site and thus decreases the rate of reaction (direct inhibition). Enzyme inhibitors may act 1-to Inhibit detoxification enzymes and 2-reduce the elimination rate of enzyme drugs, thereby having dose-dependent toxicity effects. For example, many medicines are based on the inhibition of Cytochromes P450 (CYPs) proteins, which are a superfamily of enzymes required for drug metabolism.
Answer:
As a cell grows, its surface area-to-volume ratio decreases
Answer:
The next generation average time to flowering will be 98 days.
Explanation:
Before answering the question, we need to know a few concepts.
- Artificial selection is the selecting practice of a specific group of organisms in a population -that carry the traits of interest- to be the parents of the following generations.
- Parental individuals carrying phenotypic values of interest are selected from the whole population. These parents interbreed, and a new generation is produced.
- The selection differential, SD, is the difference between the mean value of the trait in the population (X₀) and the mean value of the parents, (Xs). So,
SD = Xs - X₀
- Heritability in the narrow-sense, h², is the genetic component measure to which additive genetic variance contributes. The heritability might be used to determine how the population will respond to the selection done, R.
h² = R/SD
- The response to selection (R) refers to the metric value gained or lost from the cross between the selected parents. R can be calculated by multiplying the heritability h², with the selection differential, SD.
R = h²SD
R also equals the difference between the new generation phenotypic value (X₁) and the original population phenotypic value (X₀),
R = X₀ - X₁
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Now that we know these concepts and how to calculate them, we can solve the proposed problem.
<u>Available data: </u>
- trying to decrease the maturation time in a population of sunflowers.
- the population mean time to flower is 100 days → X₀
- Chosen parental Plants mean flowering time is 90 days → Xs
- the narrow-sense heritability for flowering time is 0.2 → h²
According to what we sow previously, we need to find out the value of X₁, which reflects the next generation average time to flowering.
- We know that R = X₁ - X₀, so we need to clear this formula to calculate X₁
X₁ = R + X₀
We already know that X₀ = 100 days,
Now we need to calculate R.
We know that h² = 0.2,
Now we need to calculate SD
Xs = 90 days → Parentals media flowering time
X₀ = 100 → Population media flowering time
SD = Xs - X₀
SD = 90 - 100
SD = - 10 days
Knowing this, we can calculate R
o h² = 0.2
o SD = - 10
R = 0.2 x (-10)
R = - 2
- Finally, once we know the R-value we can calculate the X₁ value
X₁ = R + X₀
X₁ = - 2 + 100
X₁ = 98
