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Answer:
y = 2/3x - 5 or in standard form 3y = 2x - 5
Step-by-step explanation:
Remember this fact: Parallel lines have the same slope
Step 1 Solve for y so that the equation is in the slope- intersect form
2x - 3y = 6
-3y = -2x + 6
-3y/-3 = -2x/-3 + 6/-3
y = 2/3 x -2
now we know the slope is 2/3 or
when the equation is in Standard form Ax + By = C you can use this fact: slope = - A/B so the slope = -2/-3 = 2/3
Remember the Parallel lines have the same slope
Find the y-intersect "b" use the slope = 2/3 and point (6, -1)
y = mx + b
-1 = 2/3(6) + b
-1 = 4 + b
-5 = b
Now write the equation of line that is parallel to the given line and passes through point (6, -1)
y = 2/3x - 5 or in standard form 3y = 2x - 5
Answer:
option B
(−1, 0) and (0, 6)
Step-by-step explanation:
Given in the question two equations,
Equation 1
y =−x² + 5x + 6
Equation 2
−6x + y = 6
plug value of y in second equation
−6x −x² + 5x + 6 = 6
-x² -6x + 5x +6 - 6 = 0
-x² - x + 0 = 0
-x² -x = 0
-x(x+1) = 0
x = 0
and
x = -1
plug value of x in second equation to find y
x = 0
−6(0) + y = 6
0 + y = 6
y = 6
and
x = -1
−6(-1) + y = 6
6 + y = 6
y = 0
Answer:
2/21
Step-by-step explanation:
17/21 -(3/7 + 2/7)
First you add
=17/21 - (5/7)
Then you want to subtract
=2/21