Answer:
A reasonable way to use them is to code the five most-common strings in the ... bytes, compared to a bitmap size of only 6 × 8 bits = 6 bytes. ... Columns 2, 4, 5, and 7 yield the six runs 0,5,1,1,1,eol each. ... 2.3: Replacing 10 by 3 we get x = k log2 3 ≈ 1.58k. ... Table Ans.3: Probabilities and Entropies of Two Symbols.
Step-by-step explanation:
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The answer is 17 and 19/25
Answer:
181510
Step-by-step explanation:
120,000 x1.03∧14=181510.767
Round the answer down as you can't have 0.767 of a person.
Answer:
see explanation
Step-by-step explanation:
Using the identity
tan²x = sec²x - 1
Consider left side
sec²x + tan²x
= sec²x + sec²x - 1
= 2sec²x - 1
= right side , thus verified
10000x8%= $800 anually
anually=yearly
800x18=14400
