Answer:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
Step-by-step explanation:
Given that a random sample of ten containers is selected, and the net contents (oz) are as follows: 12.03, 12.01, 12.04, 12.02, 12.05, 11.98, 11.96, 12.02, 12.05, and 11.99.
We find mean = 11.015
Sample std deviation = 3.157
a) 
(Right tailed test)
Mean difference /std error = test statistic

p value =0.174
Since p >0.01, our alpha, fail to reject H0
Conclusion:
There is no statistical evidence at 1% level to accept that the mean net contents exceeds 12 oz.
<h2>
Answer: a = ¹/₂ (4 + b)</h2>
<h3>
Step-by-step explanation:</h3>
To solve for 'a' we have to make it the subject of the equation. Since there are two unknowns ('a' & 'b'), we won't get a numerical value of 'a', but an expression in terms of the second unknown 'b'.
Since 2a - b = 4 <em> [add 'b' to both sides]</em>
then 2a = 4 + b <em>[divide both sides by 2 = multiplying by ¹/₂]</em>
a = ¹/₂ (4 + b)
Answer:
18.248287
8.2
Step-by-step explanation: