Complete question :
Wright et al. [A-2] used the 1999-2000 National Health and Nutrition Examination Survey NHANES) to estimate dietary intake of 10 key nutrients. One of those nutrients was calcium in all adults 60 years or older a mean daily calcium intake of 721 mg with a standard deviation of 454. Usin these values for the mean and standard deviation for the U.S. population, find the probability that a randonm sample of size 50 will have a mean: (mg). They found a) Greater than 800 mg b) Less than 700 mg. c) Between 700 and 850 mg.
Answer:
0.10935
0.3718
0.9778
0.606
Step-by-step explanation:
μ = 721 ; σ = 454 ; n = 50
P(x > 800)
Zscore = (x - μ) / σ/sqrt(n)
P(x > 800) = (800 - 721) ÷ 454/sqrt(50)
P(x > 800) = 79 / 64.205295
P(x > 800) = 1.23
P(Z > 1.23) = 0.10935
2.)
Less than 700
P(x < 700) = (700 - 721) ÷ 454/sqrt(50)
P(x < 700) = - 21/ 64.205295
P(x < 700) = - 0.327
P(Z < - 0.327) = 0.3718
Between 700 and 850
P(x < 850) = (850 - 721) ÷ 454/sqrt(50)
P(x < 850) = 129/ 64.205295
P(x < 700) = 2.01
P(Z < 2.01) = 0.9778
P(x < 850) - P(x < 700) =
P(Z < 2.01) - P(Z < - 0.327)
0.9778 - 0.3718
= 0.606
Answer:
he whent up and not down and left and not right
Step-by-step explanation:we just is messed up in life
Thwre are 28 clients who don not play any of the instrument using the principle of Venn distribution.
<u>Using a Venn diagram analogy</u> :
- Total number of client, U = 108
- Piano, P = 42
- Guitar, G = 51
- Piano and Guitar, (PnG) = 13
- None =?
<u>From the information given</u> :
- P only = 42 - 13 = 29
- G only = 51 - 13 = 38
<u>The total number of clients can be related thus</u> :
- Total = P only + G only + PnG + None
108 = 29 + 38 + 13 + None
108 = 80 + None
None = 108 - 80
None = 28
Therefore, the number of clients who do not play any of the instruments is 28
Learn more :brainly.com/question/12570490
Answer:
4
Step-by-step explanation:
You see the hunderth digit has a 8, so you round up. 0.9+0.1=1 so you add 1 to 3, so 3.987 rounded is 4
