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3 years ago

There are 6 rental cars available for 18 riders, each holding either 2 or 4 riders. how many rental cars hold exactly 2 riders?

Mathematics

1 answer:

Tema [17]3 years ago

8 0

Answer:

Cars for 2 riders are 3

Step-by-step explanation:

I. When total riders is 18

4(3) = 12 => Cars for 4 riders

2(3) = 6 => Cars for 2 riders

Got more question or something to discuss, leave comment below

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What is 5/8 + 3/4 divided by -2 /3 - 5/6

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$\text{Hey there!}$

$\frac{5}{4}+\frac{3}{4}\div-\frac{2}{3}\ -\ \frac{5}{6}$

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$\boxed{\boxed{\bf{Answer:\frac{-11}{12}}}}\checkmark$

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Sloan [31]

The difference quotient for the function f(x) is $h+2x-7$

Given :

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$\frac{\left(f\left(x+h\right)-f\left(x\right)\right)}{h}$

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replace x with x+h

$f(x) = x^2 - 7x + 8 \\f(x+h)=\mathrm{ }\left(x+h\right)^2-7\left(x+h\right)+8\\Expand \; and \; simplify\\f(x+h)=x^2+2xh+h^2-7\left(x+h\right)+8\\f(x+h)=x^2+2xh+h^2-7x-7h+8$

Now replace it in our formula and also replace f(x)

$\frac{\left(f\left(x+h\right)-f\left(x\right)\right)}{h}\\ \frac{x^2+2xh+h^2-7x-7h+8-(x^2 - 7x + 8)}{h} \\\frac{x^2+2xh+h^2-7x-7h+8-x^2 + 7x - 8}{h} \\\\\frac{h^2+2xh-7h}{h}\\factor \; out \; h\\\frac{h\left(h+2x-7\right)}{h}\\h+2x-7$

Learn more :brainly.com/question/23630564

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