Step-by-step explanation:
Hi there!
The given equation is:
y = -2x + 5………………(i)
Comparing the equation with y = mx+c, we get;
m1 = -2
Also another equation of the line which passes through point (-4,2), we get;
(y-2) = m2(X+4)............(ii) { using the formula (y-y1) = m2(x-x2)}
According to the question, they are perpendicular to eachother, So according to the condition of perpendicular lines;
m1*m2 = -1
-2*m2 = -1
or, m2 = 1/2.
Therefore, m2= 1/2.
Now, keeping the value of m2 in equation (ii).
(y-2) = 1/2(x+4)
y = (1/2)x + 4
Therefore, the required equation is: y = (1/2)x + 4.
<u>Hope</u><u> it</u><u> helps</u><u>!</u>
For this you use A=Pe^(rt)
A=furutre amount
P=present amount
e=natural base
r=rate in decimal
t=times in years
A=?
P=5000000
r=0.04
t=30
A=5,000,000e^(0.04*30)
A=5,000,000e^(1.2)
A=16600584.613683
In algebra a term is a single number or letter so in this 5
x^2
-10xy
3y
y^2
-1
these are all the terms
Subtract the second equation from the first equation.
x = -1
Plug -1 back in to either equation and solve for y.
3(-1) + y =-10
-3 + y = -10
Add 3 to both sides
y = -7
CHECK
3(-1) -7 = -10
2(-1) -7 = -9
(-1, -7)
Answer:
The points are: (16.12,0),(-8.12,0).
Step-by-step explanation:
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
.
This polynomial has roots 
such that 
, given by the following formulas:
Distance between two points:
Suppose we have two points, 
and 
. The distance between them is given by:
Find all points on the x-axis that are 14 units from the point (4, -7).
Being on the x-axis mean that they have y-coordinate equal to 0, so the point is (x,0).
The distance is 14. So
So 
The points are: (16.12,0),(-8.12,0).
