Three thousand five hundred and sixteen hundredths.
Answer:
the minimum records to be retrieved by using Chebysher - one sided inequality is 17.
Step-by-step explanation:
Let assume that n should represent the number of the students
SO, 
can now be the sample mean of number of students in GPA's
To obtain n such that 
⇒ 
However ;
![E(x^2) = D\int\limits^4_2 (2+e^{-x})dx \\ \\ = \dfrac{D}{3}[e^{-4} (2e^x x^3 -3x^2 -6x -6)]^4__2}}= 38.21 \ D](https://tex.z-dn.net/?f=E%28x%5E2%29%20%3D%20D%5Cint%5Climits%5E4_2%20%282%2Be%5E%7B-x%7D%29dx%20%5C%5C%20%5C%5C%20%3D%20%5Cdfrac%7BD%7D%7B3%7D%5Be%5E%7B-4%7D%20%282e%5Ex%20x%5E3%20-3x%5E2%20-6x%20-6%29%5D%5E4__2%7D%7D%3D%2038.21%20%5C%20D)
Similarly;
⇒ 
⇒ 
⇒ 
∴ 
Now; 
Using Chebysher one sided inequality ; we have:
So; 
⇒ 
∴ 
To determine n; such that ;
⇒ 
Thus; we can conclude that; the minimum records to be retrieved by using Chebysher - one sided inequality is 17.
Answer: b
Step-by-step explanation:
You can determine which is a function by looking at the x values. If an x value repeats, it is not a function. In A, the x variable 2 repeats so it is not a function. In C, the x variable 5 repeats. In D, the x variable -5 repeats. The only answer choice where none of the x values are the same is B, so the answer is B. Hope this helps!
(5 7/8-6 3/4)-2 1/4
Solve the numbers in the parenthesis ( I change the denominators to a common denominator that 8 and 4 share)
(5 7/8 - 6 3/4)-2 1/4
^
-1 1/8-2 1/4
(I use KKC aka Keep Change Change where I keep -1 1/8 the same, change the minus sign to a plus sign, and change the -2 1/4 to positive) ( I change the denominators to a common denominator that 8 and 4 share)
-1 1/8 + +2 1/4 = 1 1/8
Answer:
- 2x - 31
Step-by-step explanation:
Given
- 3(4x + 5) - 2(- 5x + 8)
Multiply the terms in the first parenthesis by - 3 and the terms in the second parenthesis by - 2
= - 12x - 15 + 10x - 16 ← collect like terms
= (- 12x + 10x) + (- 15 - 16)
= - 2x - 31
