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svetlana [45]
3 years ago
12

An astronaut weighs 685 N on earth. What would the astronaut's weight (in FORCE) be on Jupiter where gravity= 25.9 m/s2? (*Tip:

Solve for the astronaut’s MASS in the Earth, and then procced with his weight, in Newton in Planet Jupiter.) Use G-R-E-S-A, Given. Required, Equation, Solution, Answer
Mathematics
1 answer:
VladimirAG [237]3 years ago
3 0

Answer:

Step-by-step explanation:

I'm sure by now you have learned the difference between mass and weight. Mass will never change regardless of where something is while weight changes depending upon the pull of gravity. If we want the mass, then we have to take the weight on Earth and divide by its pull of gravity. The equation for that will be

W = mg where W is the weight in Newtons, m is mass and g is gravity.

685 = m(9.8) so

m = 7.0 × 10¹ kg

Now that we know that mass, and also because we know that the mass is constant no matter where the astronaut is, we can find his weight on Jupiter.

W = (7.0 × 10¹)(25.9) so

W = 1800 N

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krek1111 [17]

Answer:

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Step-by-step explanation:

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Un cono ha l'area laterale di 255 pigreco cm^2, l'apotema di 17 cm e pesa 900 pigreco g. Calcola il peso specifico del materiale
valkas [14]

Answer:

The specific weight is 1.5\frac{g}{cm^{3}}

Step-by-step explanation:

The question in English

A cone has a lateral area of 255 pi cm^2, an apothem of 17 cm and weighs 900 pi g. It calculates the specific weight of the material of which it is composed

step 1

Find the radius of the cone

we know that

The lateral area of a cone is equal to

LA=\pi rl

we have

LA=255\pi\ cm^{2}

l=17\ cm

substitute the values

255\pi=\pi r(17)

Simplify

255=r(17)

r=255/(17)=15\ cm

step 2

Find the height of the cone

Applying the Pythagoras Theorem

l^{2} =r^{2} +h^{2}

substitute the values and solve for h

17^{2} =15^{2} +h^{2}

h^{2}=17^{2}-15^{2}

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step 3

Find the volume of the cone

The volume of the cone is equal to

V=\frac{1}{3}\pi r^{2}h

substitute the values

V=\frac{1}{3}\pi (15)^{2}(8)

V=600\pi\ cm^{3}

step 4

Find the specific weight

Divide the mass by the volume

\frac{900\pi }{600\pi}=1.5\frac{g}{cm^{3}}

4 0
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Answer:

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With $5 she will be able to purchase 5/0.08083=61.85 pencils

We must round to the nearest lower integer

The teacher can purchase 61 pencils with $5

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The fraction is 5/6
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