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Elan Coil [88]
3 years ago
11

Three forms of radiation are also called ionizing radiation

Chemistry
1 answer:
Trava [24]3 years ago
8 0

Answer:

Alpha Particle, Beta Particles and Gamma Rays

Explanation:

You might be interested in
Name the following compound: CH₂-C- CH₂-CH₂-CH₂-C - H butanal O2-butanol O propyl hydrogen ether 1-propanone​
bulgar [2K]

Answer:

butanal

Explanation:

It's not 1-propanone because otherwise you have OH bonded to C not O and H bonded to C separately. 2-butanol means that the O and H would be bonded to a different C atom, and it's not propyl hydrogen ether because the O would be in the chain of bonded Cs.
Hope this helps :)

6 0
3 years ago
Strontium carbonate + sulphuric acid, chemical equation​
tangare [24]
<h3>Answer:</h3>

SrCO₃ + H₂SO₄ → SrSO₄ + H₂O + CO₂

<h3>Explanation:</h3>

We are required to complete the chemical equation given;

strontium carbonate + sulfuric acid → ??

  • We know that, carbonates reacts with acids to form a salt, water and carbon dioxide.
  • Strontium carbonate reacts with sulfuric acid to form strontium sulfate, water and carbon dioxide.
  • Therefore, the equation for the reaction is;

SrCO₃ + H₂SO₄ → SrSO₄ + H₂O + CO₂

  • The equation is balanced as the number of atoms of each element are equal on both sides of the equation.
7 0
3 years ago
an alloy composed of tin, lead, and cadmium is analyzed. the mole ratio of sn:pb is 2.73:1.00, and the mass ratio of pb:cd is 1.
nordsb [41]

This problem is describe the mole-ratio composition of an allow composed by tin, lead and cadmium. Ratios are given as Sn:Pb 2.73:1.00 and Pb:Cd is 1.78:1.00, and we are asked to calculate the mass percent compositon of Pb in the allow.

In this case, according to the given information, it turns out possible realize that the following number of moles are present in the alloy, according to the aforementioned ratios:

2.73mol Sn\\\\1.00molPb\\\\\frac{1.00molPb*1.00molCd}{1.78molPb}= 0.562molCd

Next, we calculate the masses by using each metal's atomic mass:

m_{Sn}=2.73mol*\frac{118.7g}{1mol}=324.05g\\\\ m_{Pb}=1.00mol*\frac{207.2g}{1mol}=207.2g\\\\m_{Cd}=0.562mol*\frac{112.4g}{1mol}=63.2g

Thus, the mass percent composition of each metal is shown below:

\%Sn=\frac{324.05g}{324.05g+207.2g+63.2g} *100\%=54.5\%\\\\\%Pb=\frac{207.2g}{324.05g+207.2g+63.2g} *100\%=34.9\%\\\\\%Cd=\frac{63.2}{324.05g+207.2g+63.2g} *100\%=10.6\%

So that of lead is 34.9 %.

  • brainly.com/question/19168996
  • brainly.com/question/2578569

Learn more:

8 0
3 years ago
How many moles of H2O are in 36 grams of water?
saw5 [17]

Answer:

2 moles

Explanation:

number of mole =mass /molar mass

mass=36

molar mass=(2*1)+16=18

therefore, no of mole =36÷18 =2

4 0
3 years ago
what is the formula equation for the reaction between sulfuric acid and dissolved sodium hydroxide if all products and reactants
Rama09 [41]
This reaction would produce salt and water- Sodium Sulphate and Water.

H₂SO₄ + 2NaOH  →  Na₂SO₄ +  2H₂O
4 0
4 years ago
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