Three forms of radiation are also called ionizing radiation
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is the type of orbital hybridization of a central atom that has one lone pair and bonds to four other atoms.
In the context of valence bond theory, orbital hybridization (or hybridisation) refers to the idea of combining atomic orbitals to create new hybrid orbitals (with energies, forms, etc., distinct from the component atomic orbitals) suited for the pairing of electrons to form chemical bonds.
For instance, the valence-shell s orbital joins with three valence-shell p orbitals to generate four equivalent sp3 mixes that are arranged in a tetrahedral configuration around the carbon atom to connect to four distinct atoms.
Hybrid orbitals are symmetrically arranged in space and are helpful in the explanation of molecular geometry and atomic bonding characteristics. Usually, atomic orbitals with similar energies are combined to form hybrid orbitals.
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Taking into account about the ideal gas law, the mass of fluorine gas is 63.2244 grams.
<h3>What is ideal gas law</h3>An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:
P×V = n×R×T
where:
- P is the gas pressure.
- V is the volume that occupies.
- T is its temperature. The universal constant of ideal gases R has the same value for all gaseous substances.
- R is the ideal gas constant.
- n is the number of moles of the gas.
The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.
<h3>Mass of fluorine gas</h3>In this case, you know:
- P= 850 mmHg= 1.11842 atm (being 1 mmHg= 0.00131579 atm)
- V= 45.5 L
- T =100 °C= 373 K (being 0°C= 273 K)
- R= 0.082
- n= ?
Replacing in the ideal gas law:
1.11842 atm ×45.5 L = n×0.082 × 373 K
Solving:
n= (1.11842 atm ×45.5 L)÷ (0.082 × 373 K)
<u><em>n= 1.6638 moles</em></u>
The molar mass of F₂ is 38 g/mole. Then you can apply the folowing rule of three: If by definition of molar mass 1 mole of the compound contains 38 grams, 1.6638 moles of the compound contains how much mass?
<u><em>mass= 63.2244 grams</em></u>
Finally, the mass of fluorine gas is 63.2244 grams.
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