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Paraphin [41]
3 years ago
9

g When a species can be represented by two or more resonance structures, the actual representation of bonding in the species is

given by: A. the resonance structure with no multiple bonds B. the resonance hybrid of all structures C. the best resonance structure D. the resonance structure with no lone pairs on the central atom. E. the resonance structure with the most multiple bonds
Chemistry
2 answers:
AlekseyPX3 years ago
6 0

Answer:

B. the resonance hybrid of all structures

Explanation:

The idea of resonance is used to explain bonding in compounds where a single structure does not fully account for all the bonding interactions in a molecule.

A number of equivalent structures are then used to show the nature of bonding in such a molecule. Such structures are called resonance structures or canonical structures. None of these structures individually offer a holistic explanation to the bonding interactions in the molecule under study.

However, a hybrid of all the canonical structures does explain the nature of bonding in the molecule.

Luba_88 [7]3 years ago
4 0

Answer:

B. the resonance hybrid of all structures

Explanation:

When a species can be represented by two or more resonance structures, the actual representation of bonding in the species is given by: <u>the resonance hybrid of all structures</u>

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If 12.4 mol of Ne gas occupies 122.8 L, how many mol of Ne would occupy 339.2 L under the same temperature and pressure? Record
8090 [49]

Answer:

3.43×10¹ mol

Explanation:

Given data:

Initial number of  moles = 12.4 mol

Initial volume = 122.8 L

Final number of moles = ?

Final volume = 339.2 L

Solution:

The number of moles and volume are directly proportional to each other at same temperature and pressure.

V₁/n₁  =  V₂/n₂

122.8 L/ 12.4 mol  =  339.2 L / n₂

n₂ = 339.2 L× 12.4 mol  / 122.8 L

n₂ = 4206.08 L.mol /122.8 L

n₂ = 34.3mol

In scientific notation:

3.43×10¹ mol

7 0
3 years ago
Aluminum and oxygen react according to the following equation: 4Al + 3O2 -&gt; 2Al2O3 In a certain experiment, 4.6g Al was react
stiv31 [10]

Answer:

Percent yield: 78.2%

Explanation:

Based on the reaction:

4Al + 3O₂ → 2Al₂O₃

<em>4 moles of Al produce 2 moles of Al₂O₃</em>

<em />

To find percent yield we need to find theoretical yield (Assuming a yield of 100%) and using:

(Actual yield (6.8g) / Theoretical yield) × 100

Moles of 4.6g of Al (Molar mass: 26.98g/mol) are:

4.6g Al × (1mol / 26.98g) = 0.1705 moles of Al.

As 4 moles of Al produce 2 moles of Al₂O₃, theoretical moles of Al₂O₃ obtained from 0.1705 moles of Al are:

0.17505 moles Al × (2 moles Al₂O₃ / 4 moles Al) = <em>0.0852 moles of Al₂O₃</em>,

In grams (Molar mass Al₂O₃ = 101.96g/mol):

0.0852 moles of Al₂O₃ × (101.96g / mol) =

<h3>8.7g of Al₂O₃ can be produced (Theoretical yield)</h3>

Thus, Percent yield is:

(6.8g / 8.7g) × 100 =

<h3>78.2% </h3>
8 0
3 years ago
Analyze complete and balance the following equation co2(g)+hcl(aq)
Anna007 [38]

Answer:

CO_{2} (g)+4HCl(aq)->2H_{2} O(g)+CCl_{4} (g)

This is a double displacement reaction, C goes with Cl in the products side and O2 goes with H. All that is left is to balance the equation, making sure each side has equal amounts of atoms.

4 0
2 years ago
Ok true or false
Misha Larkins [42]

Answer:

1.True

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4 0
3 years ago
He table shows the percentages of hydrocarbons that are found in a sample of crude oil.
Flura [38]

Answer is: a mixture.

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Proportion of hydrocarbons is diiferent in varios parts of the world.

Solution is homogeneous mixture composed of two or more substances.  

3 0
3 years ago
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