The sum of Potential Energy and Kinetic Energy is called Mechanical Energy
Answer: 4.29 m/s
Explanation:
Given
Depth of the well, s = 8.23 m
Time taken to reach the well, t = 0.93 s
Speed of sound = 343 m/s
To solve this, we would be using one of l the laws of motion.
S = ut + 1/2gt², where
S = depth of the well
u = initial speed of toss
g = acceleration due to gravity
t = time taken to reach the well
We would then have
8.23 = 0.93 u + 1/2 * 9.8 * 0.93²
8.23 = 0.93 u + 4.9 * 0.8649
8.23 = 0.93 u + 4.23801
0.93 u = 8.23 - 4.23801
0.93 u = 3.99199
u = 3.99199 / 0.93
u = 4.29 m/s
Therefore, the initial speed of the coin is 4.29 m/s
Answer:
Option D 3.9
Explanation:
First, you need to use the correct equation which is the following:
COP = Q/W
Where:
Q = heat absorbed
W = work done by the pump
COP = coefficient of perfomance
We have all the data, so, all you need to do is replace in the above expression and you shoould get the correct result:
COP = 30 / 7.7
COP = 3.896
This result you can round it to 3.9. option D.
Answer:
The average emf induced in the coil is
.
Explanation:
Given that,
Number of turns = 1000 turns
Area = 85 cm²
Time = 0.090 s
Its plane is perpendicular to Earth's magnetic field.
Angle = 0°
Magnetic strength
We need to calculate the magnetic flux
Using formula of magnetic flux

Put the value into the formula



We need to calculate the average emf induced in the coil

Put the value into the formula



Hence, The average emf induced in the coil is
.
Answer:
93.54 Hz
Explanation:
✓From the question, Number of harmonic frequency is 4
✓ the frequency (f₄ )= 116.5 Hz
✓harmonic frequency can be calculated using below expresion
fₙ = [ (nv)/4L]..........eqn(1)
v = speed of sound= 343 m/s
n = number of given harmonic frequency
L = Length of the rope
Using above expresion ,and substitute the values at (n=4) which is 4th harmonic frequency to find the " initial Lenght of the rope
fₙ = [ (nv)/4L]
f₄ = 4× 343 /4L
f₄ = 343 /L
L= 343 /f₄
But f₄= 116.5 Hz
L= 343/116.5= 2.944m
Hence, initial Lenght of the rope= 2.944m
We can determine the frequency of new length as ( initial Lenght of the rope + tubing Lenght)
= ( 2.944m + 0.721m )
= 3.667m
Hence, new length= 3.667m
To find the new frequency of the 4th harmonic we will use eqn(2)
f₄ = v/l ...............eqn(2)
From equation (2) If we substitute the values we have
f₄ = (343/3.667)
= 93.54 Hz
Hence, the the new frequency of the 4th harmonic is
93.54 Hz