momentum= mass × velocity = 0.141kg×1.33m/s= 0.18753kg m/s = 0.188kg m/s (3s.f.)
Answer:
cross out the false piece in blue and write the true piece in red
The work done in the isothermal process is 10 joule.
We need to know about the isotherm process to solve this problem. The isotherm process can be described as a process where the initial temperature system will be the same as the final temperature. Hence, the internal energy change will be zero.
ΔU = 0
Hence,
ΔU = Q - W
0 = Q - W
Q = W
It means that the heat transferred is the same as the work done.
From the question above, we know that the heat transferred is 10 joule. Thus, the work done in the isothermal process is 10 joule.
Find more on isothermal at: brainly.com/question/17097259
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Answer:
The work done on the wagon is 37 joules.
Explanation:
Given that,
The force applied by Charlie to the right, F = 37.2 N
The force applied by Sara to the left, F' = 22.4 N
We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :



Work done on the wagon is given by the product of net force and displacement. It is given by :


W = 37 Joules
So, the work done on the wagon is 37 joules. Hence, this is the required solution.
This is called vaporization.
hope this helps :)