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hram777 [196]
3 years ago
15

(1 point) A horizontal clothesline is tied between 2 poles, 20 meters apart. When a mass of 5 kilograms is tied to the middle of

the clothesline, it sags a distance of 2 meters. What is the magnitude of the tension on the ends of the clothesline

Physics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

Ft = 50.25 N

Explanation:

As you can see in the attached diagram, the angle θ is given by

tanθ = opp/adj

The opposite is the sag of distance 2 m and the adjacent is the half of the horizontal clothesline that is 20 m.

tanθ = 2/10

θ = tan⁻¹(2/10)

θ = 11.30°

There are two forces along the y axis, one is the F = mg acting downwards and the other is the Ftsinθ component of tension force in the string.

The sum of forces along y-axis is

5Ftsin(11.30) - mg = 0

Ft = mg/5sin(11.30)

Ft = 5*9.8/5sin(11.30)

Ft = 9.8/0.195

Ft = 50.25 N

Therefore, the magnitude of the tension on the ends of the clothesline is 50.25 N.

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Superman is supposed to leap tall buildings in a single bound. Suppose that he obeys the normal laws of physics in this feat. Es
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v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -9.81\times 50}\\\Rightarrow u=31.32\ m/s

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