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77julia77 [94]
1 year ago
13

14.A 90 kg quarterback gets tackled by being hit by a 120 kg lineman backwards

Physics
1 answer:
quester [9]1 year ago
8 0

The acceleration of the quarterback and the lineman is 5.55m/s² and 4.16m/s² respectively in the same direction.

As, we know, the 120 Kg lineman is moving with a force of 500N.

His net acceleration will be in the same direction as his motion.

It is already known that, If M is the mass of the body and a is the acceleration of the body, then the force F on the body can be calculated by using the formula,

F = Ma.

The weight of the quarterback is 90 Kg. He is being hit by a force of 500N.

So, the acceleration can be calculated using the formula,

500N = 90kg x a

a = 5.55 m/s².

Now, the weight if the lineman is 120kg, the force applied by him is 500N.

So, from the formula, his acceleration A will be,

500N = 120Kg x A

A = 4.16 m/s².

both of them will have acceleration in the same direction,

To know more about Force, visit,

brainly.com/question/25239010

#SPJ9

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What is the moving kinetic energy of a 1500kg car moving at 25m/s?
EleoNora [17]

Answer:

<h2>468,750 J</h2>

Explanation:

The kinetic energy of an object can be found by using the formula

k =  \frac{1}{2} m {v}^{2}  \\

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From the question we have

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5 0
3 years ago
Read 2 more answers
5.An ice skater pushes against a wall with a force of 59 N. Ignoring friction, if the ice skater has
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Answer:

<em>Answer: (A) 0.75 m/s^2</em>

Explanation:

The Second Newton's law states that an object acquires acceleration when an external unbalanced net force is applied to it.

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It can be expressed with the formula:

\displaystyle a=\frac{F_n}{m}

Where

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The ice skater pushes against a wall with a force of 59 N. The wall returns the force and the skater now has a net force of Fn=59 N that makes him accelerate. Being m=79 kg the mass of the skater, the acceleration is:

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