Coherent microwaves of wavelength 5.00 cm enter a tall, narrow window in a building otherwise essentially opaque to the microwav
es. if the window is 36.0 cm wide, what is the distance from the central maximum to the first-order minimum along a wall 6.50 m from the window?
1 answer:
The solution for this problem is:
For 1st minimum, let m be equal to 1.
d = slit width
D = screen distance.
Θ = arcsin (m * lambda/ (d))
= 0.13934 rad, 7.9836 deg
y = D*tan (Θ)
y = 6.50 * tan (7.9836)
= 0.91161 m is the distance from the central maximum to the first-order minimum
You might be interested in
Explanation:
If the size and direction of the forces on the object are exactly balanced , then there is no net force acting on the object
Answer:
the property of liquid are
1 they can flow from one place to another if surface is slanted
2 it cannot be compressed
Answer: 0.516 ft/s
Explanation:
Given
Length of ladder L=20 ft
The speed at which the ladder moving away is v=2 ft/s
after 1 sec, the ladder is 5 ft away from the wall
So, the other end of the ladder is at
Also, at any instant t
differentiate w.r.t.
I think it's b..................
Your answer will be False because wavelengths are usually are use as sound waves.