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Alexus [3.1K]
3 years ago
12

Hey please help i’ll give brain

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
5 0

Answer:

7 \times 6 = 5 \: sixes + 2 \: sixes \\ 7 \times 6 = 30 + 12 \\ =  42 \\  \\ thank \: you

MAXImum [283]3 years ago
4 0

Hi ;-)

7\cdot6=5 \ \text{sixes}+\boxed2 \ \text{sixes}\\\\=\boxed{30}+12\\\\=\boxed{42}

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Find the gcf of 15a and 28b^2. 9ab^2 0 3 1
lions [1.4K]
Answer:

GCF(15a; 28b²) = 1
5 0
3 years ago
Determine algebrically if f(x)=4x³-5x is odd or even function​
Gelneren [198K]

Answer:

Odd function

Step-by-step explanation:

So to see if a function is odd or even we need to plug in a negative x for x, so f(-x)=4(-x)^3-5(-x). This produces -4x^3+5x, which is the exact opposite of the original equation, so it is an odd function. If it were even, then the signs of the coefficients would be the same as the original function.

4 0
2 years ago
6051 m is equal to how many km?
Luba_88 [7]
6,051m = 6,000m + 51m

1km=1,000 metres

--------------------------------

Therefore:

6,051 metres = 6,000/1,000km + 51/1,000km

=6,051/1,000km

=6.051km
8 0
2 years ago
Read 2 more answers
Select the vertical asymptote(s) of the function <img src="https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B%28x%2B6%29%28x-1%29%7D%
Bess [88]

Answer:

As the described function, we want to find vertical asymtotes, we find the value of x so that the denominator is equal to 0.

Here, (x - 2)(x + 6) = 0

=> x = 2, x =-6

=> Option C is correct.

Hope this helps!

:)

4 0
3 years ago
Read 2 more answers
ΔEFG is located at E (0, 0), F (−7, 4), and G (0, 8). Which statement correctly classifies ΔEFG?
MariettaO [177]

Answer:

ΔEFG is an isosceles triangle.

Step-by-step explanation:

Given:

E (0, 0),

F (−7, 4),

G (0, 8)

ΔEFG

Solution:

Distance formula

Distance d = \sqrt{(x_2-x_1)^2 +( y_2-y_1)^2

Step 1: Finding the length of  EF

By using distance formula,

EF = \sqrt{(-7 - 0)^2 + (4-0)^2}

EF = \sqrt{(49) + (16)}

EF = \sqrt{(49) + (16)}\\EF = \sqrt{65}\\

Step 2: Finding the length of  FG

By using distance formula,

FG = \sqrt{(0-(-7))^2+(8-4)^2}\\FG = \sqrt{(7)^2 +(4)^2}\\FG = \sqrt{49 +16}\\FG = \sqrt{65}

Step 2: Finding the length of  GE

GE= \sqrt{(0-0)^2 + (0-8)^2}\\\\GE =\sqrt{(-8)^2}\\GE = \sqrt{64}\\GE = 8

Thus we could see that the sides EF = FG

So it is  a isosceles triangle.

6 0
2 years ago
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