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SVEN [57.7K]
2 years ago
5

(this question only goes out to that guy who said he was gonna sue me)

Mathematics
1 answer:
san4es73 [151]2 years ago
6 0

Answer:

6^3= 216

4^4=256

216*256=55296

Step-by-step explanation:

no1 should sue u boo lm.fao

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How do I solve numbers 8 and 9?
Tresset [83]
8: 20
9: 90
I am so sorry if this is wrong. I am not good at this type of things
7 0
2 years ago
The cost of hiring a taxi consists of a fixed cost of $3 plus $0.5 per kilometer distance travelled. Write an expression in term
irinina [24]

Answer:

The required expression is:

  • y = 0.5x + 3

Please check the attached graph too.

Step-by-step explanation:

The slope-intercept form of the linear or line function

y = mx+b

where

  • m is the rate of change or slope
  • b is the y-intercept

In our case,

The cost of hiring a taxi consists of a fixed cost of $3. It means the fixed cost of $3 is the initial condition.

Thus, the y-intercept b = 3

It is stated that the cost of per kilometer distance = $0.5

Thus, the rate of change or slope m = 0.5

As y represents the cost and x represents the number of kilometers.

so substituting m = 0.5 and b = 3 in the slope-intercept form of the linear or line function

y = mx+b

y = 0.5x + 3

Thus, the required expression is:

  • y = 0.5x + 3

Please check the attached graph too.

5 0
3 years ago
What is the greatest common factor of 42,28 and 70?
eduard

Answer:

the greatest common factor would be 14 . Hope this helped

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B25%20%7D%7B5%20%7D%20%20%2B%20%20%5Cfrac%7B1%7D%7B5%7D%20" id="TexFormula1" title
Sliva [168]
Answer:
25/5+1/5
=5+1/5
=26/5
6 0
3 years ago
Which set of parametric equations over the interval 0 ≤ t ≤ 1 defines a line segment with initial point (–5, 3) and terminal poi
Ksivusya [100]

Given:

A line segment with initial point (–5, 3) and terminal point (1, –6).

To find:

The set of parametric equations over the interval 0 ≤ t ≤ 1 which defines the given line segment.

Solution:

Initial point is (–5, 3). So,

x(0)=-5,y(0)=3

Terminal point is (1, –6).

x(1)=1,y(1)=-6

Check which of the given set of parametric equations satisfy x(0)=-5,y(0)=3,x(1)=1,y(1)=-6.

Put t=1 in each set of parametric equations.

In option A,

y(1)=3-6(1)=3-6=-3\neq -6

So, option A is incorrect.

In option B,

y(1)=1-6(1)=1-6=-5\neq -6

So, option B is incorrect.

In option C,

y(1)=3-9(1)=3-9=-6

x(1)=-5+6(1)=-5+6=1

Put t=0, in this set of parametric equations.

x(0)=-5+6(0)=-5

y(0)=3-9(0)=3

So, option C is correct.

In option D,

y(1)=1-7(1)=1-7=-3\neq -6

x(1)=-5+8(1)=-5+8=3\neq 1

So, option D is incorrect.

8 0
3 years ago
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