Heat transfer is limited to conduction and radiation only in anomalous expansion of water simply because of the temperature at which the expansion occurs and density
<h3>What is anomalous expansion of water?</h3>
Anomalous expansion of water is a property of water in which water expands instead of contracting.
- Anomalous expansion of water makes water less dense.
- The major effect of this anomalous expansion it will still remain less dense and at the surface of water.
- Interestingly, this expansion occurs when it is cooled from 4°C to 0°C.
Learn more about properties of water:
brainly.com/question/18681949
True. The question describes the idea of energy conservation faithfully. Energy can change forms but remains the same within an isolated system over time. Within such a system, energy cannot be created or destroyed.
A thermostat is a switch that operates itself when the temperature
goes above or below a temperature that the user can set.
-- Before you go to bed, you set the thermostat for 65° .
If the temperature in the house goes below 65° during the night,
the thermostat turns on the furnace, and keeps it running until
the house warms up to 65°. Then it shuts the furnace off.
-- After breakfast, you set the thermostat for 75°.
If the temperature in the house goes above 75°, during the day,
the thermostat turns on the air conditioner, and keeps it running until
the house cools down to 75°. Then it shuts the air conditioner off.
-- On Sunday morning, you put the slow cooker on the kitchen counter,
and you throw in a big roast, a sliced onion, some baby carrots, some
sliced potatoes, some vegetable stock, salt, pepper, garlic, chili powder,
and tomato paste. Then you put the cover on, turn the power on, and
set the slow cooker to "LOW". The heater in the slow cooker turns on.
Whenever the temperature in the crock gets higher than 160°, the
thermostat in the slow cooker turns off the heater, and keeps it off
until the crock cools down to 160°. Then the thermostat turns the
heater on again.
By dinner time, you have a hot, juicy, scrumptious pot roast, ready
to eat. It's not too hot, not too cold, not too tough, not dried out, and
it melts in your mouth.
You're still thinking about it when you go to bed, and your mom gives you
a slice to take to school for your lunch on Monday.
Answer:
Option D. 9.47 V
Explanation:
We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:
Resistor 1 (R₁) = 20 Ω
Resistor 2 (R₂) = 30 Ω
Resistor 3 (R₃) = 45 Ω
Equivalent Resistance (R) =?
R = R₁ + R₂ + R₃ (series connections)
R = 20 + 30 + 45
R = 95 Ω
Next, we shall determine the current in the circuit. This can be obtained as follow:
Voltage (V) = 45 V
Equivalent Resistance (R) = 95 Ω
Current (I) =?
V = IR
45 = I × 95
Divide both side by 95
I = 45 / 95
I = 0.4737 A
Finally, we shall determine, the voltage across R₁. This can be obtained as follow:
NOTE: Since the resistors are in series connection, the same current will pass through them.
Current (I) = 0.4737 A
Resistor 1 (R₁) = 20 Ω
Voltage 1 (V₁) =?
V₁ = IR₁
V₁ = 0.4737 × 20
V₁ = 9.47 V
Therefore, the voltage across R₁ is 9.47 V.
