Answer:
They both cross the finish line with the same kinetic energy
Explanation:
Same force, same displacement, so same KE at the location of the finish line. They don’t cross the line at the same time, but that was not the question!
∆KA= (mA/2)vF,A2
∆KA=∆KBso vF,B/vF,A= (MA/MB)1/2∆KB= (mB/2)vF,B2
Lighter boat goes faster so reaches finish line 1st
Answer:
Guessing you just need help with the definition but if it's the question I can still help you.
The distance at which the man slips is 0.3 m
Newton's Second Law, F = ma, is used to calculate the braking distance. By dividing the mass of the car by the gravitational acceleration, one may determine its weight. The weight of the car multiplied by the coefficient of friction equals the brake force.
Given-
mass of man= 70 kg
frictional coefficient μ=0.02
mass of body thrown= m2 = 3kg
let s be the stopping distance
we know that frictional force = F= μN
=μMg= 0.02 x 70 x 10
=14 N
∴acceleration, a= 14/70 = 0.2 m/s²
now on applying conservation of linear momentum
pi=pf pi=0 (initially at rest)
0=m1v1-m2v2 (v1= velocity of man) (v2=velocity of body= 8m/s
v1= m2v2 /m1= 0.3 m/s
we know,
v²- u² = -2as
0- (0.3) ²= -2 x 0.2 x 5
s= 0.09/0.4 ≈ 0.3 m
Learn more about distance here-
brainly.com/question/15172156
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so, 444 eggs would have been released in 37yrs
<h2>Answer:</h2><h3>D. ability to react with oxygen</h3><h2>Explanation:</h2>
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