P14.003A spherical gas-storage tank with an inside diameter of 8.1 m is being constructed to store gas under an internal pressur
1 answer:
Answer:
The minimum wall thickness required for the spherical tank is 0.0189 m
Explanation:
Given data:
d = inside diameter = 8.1 m
P = internal pressure = 1.26 MPa
σ = 270 MPa
factor of safety = 2
Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?
The allow factor of safety:
The minimun wall thickness:
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Answer:
Approximately 6.8 x 10⁻¹⁵
Explanation:
To be able to get this fraction, there are some things we need to know.
1. The radius of nucleus = 1.0 x 10⁻¹³ cm
2. The radius of hydrogen atom = 52.9 pm
3. Volume of sphere = V1/V2 = (R1/R2)^3
4. 1 picometer (pm) = 10^-10 cm
CHECK ATTACHMENT FOR Step by step solution to the answer
Answer:
a) Q1=Q2=480μC V1=240V V2=60V
b) Q1=96μC Q2=384μC V1=V2=48V
c) Q1=Q2=0C V1=V2=0V
Explanation:
Let C1 = 2μC and C2=8μC
For part (a) of this problem, we know that charge in a series circuit, is the same in C1 and C2. Having this in mind, we can calculate equivalent capacitance first:
For part (b), the capacitors are in parallel now. In this condition, the voltage is the same for both capacitors:
So,
Total charge is the same calculated for part (a), so:
Solving for Q2:
Q2 = 384μC Q1 = 96μC.
Therefore:
V1=V2=48V
For part (c), both capacitors would discharge, since their total voltage of 300V would by applied to a wire (R=0Ω). There would flow a huge amount of current for a short period of time, and capacitors would be completely discharged. Q1=Q2=0C V1=V2=0V