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makvit [3.9K]
3 years ago
8

Bob is threatening Tom’s life with a giant laser with wavelength (650 nm), a distance (D = 10 m) from the wall James is shackled

to. (He is still free to move along the wall.) Bob has set up a double slit experiment and Tom must figure out where to position himself such that he is at a point of destructive interference to survive. If the double slit separation is d = 5 μm, where can Tom stand to avoid a laser-full demise?
Physics
1 answer:
Fittoniya [83]3 years ago
8 0

Answer:

He should stand from the center of laser pointed on the wall at 1.3 m.

Explanation:

Given that,

Wave length = 650 nm

Distance =10 m

Double slit separation d = 5 μm

We need to find the position of fringe

Using formula of distance

d\sin\theta=n\lambda

d\dfrac{y}{D}=n\lambda

y=\dfrac{\lambda D}{d}

Put the value into the formula

y=\dfrac{650\times10^{-9}\times10}{5\times10^{-6}}

y=1.3\ m

Hence, He should stand from the center of laser pointed on the wall at 1.3 m.

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