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3 years ago

CAN SOMEONE PLS HELP ME !!

Mathematics

1 answer:

algol [13]3 years ago

8 0

The answer is $1505.76

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8 out of 10 dentists prefer Crest toothpaste what is the ratio of dentist who dont prefer crest toothpaste than those who do?

Nata [24]

Answer:

1:4

Step-by-step explanation:

If 8/10 prefer Crest, that means 2/10 don't prefer it.

To find the ratio, put together the number that don't prefer it to the number that does:

2:8

Simplify by dividing each side by 2:

1:4

So, the ratio is 1:4

4 0

3 years ago

Last one i need help with to move on! I have a pic of the question

adoni [48]

length = 4 yards and width = 3.5 yards

let width be w then length is 2w - 3

area = w(2w - 3) = 14 (rearrange in standard form )

2w² - 3w - 14 = 0 ← in standard form

(2w - 7 )(w + 2 ) = 0 ← in factored form

equate each factor to zero and solve for w

2w - 7 = 0 ⇒ w = 3.5

w + 2 = 0 ⇒ w = - 2

but w > 0, hence w = 3.5

width = 3.5 yards and length = (2 × 3.5 ) - 3 = 4 yards

8 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs.

Len [333]

<u>Answer:</u>

1. $(-2^2)^{-6}$ ÷ $(2^{-5})^{-4} \implies 2^{-32}$

2. $2^4 . (2^2)^{-2} \implies 1$

3. $(-2^{-4}).(2^2)^0 \implies -2^8$

4. $(2^2).(2^3)^{-3} \implies 2^{-5}$

<u>Step-by-step explanation:</u>

1. $(-2^2)^{-6}$ ÷ $(2^{-5})^{-4}$ :

$= \frac{ ( - 2 ^ 2 ) ^ { - 6 } } { ( 2 ^ { - 5 } ) ^ { - 4 } } = \frac{2^{-12}}{2^{20}} = 2^{-12-20}=2^{-32}$

2. $2 ^ 4 . ( 2 ^ 2 ) ^ { - 2 }$ :

$= 2^4 \times \frac{1}{2^4} = 1$

3. $(-2^{-4}).(2^2)^0$ :

$= (-2^4)^2 \times 1 = -2^8$

4. $(2^2).(2^3)^{-3}$ :

$= 2^4 \times \frac{1}{2^9} =\frac{1}{2^5} =2^{-5}$

5 0

3 years ago

Read 2 more answers

Sin 30*=square root 3/2 true or false

Sphinxa [80]

Answer:

Step-by-step explanation:

Sin(30o) = 0.5 or 1/2

Sin(60o) = sqrt(3)/2

So the statement is false

5 0

3 years ago

Pls help i am on a timer

stich3 [128]

Answer:

$x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}$

Step-by-step explanation:

Given;

x² - 2x - 1 = 0

Solve by completing the square method;

⇒ take the constant to the right hand side of the equation.

x² - 2x = 1

⇒ take half of coefficient of x = ¹/₂ x -2 = -1

⇒ square half of coefficient of x and add it to the both sides of the equation

$x^2 + (-1)^2 = 1 + (-1)^2$

$(x-1)^2 = 1 + 1\\\\(x-1)^2 = 2\\\\$

⇒ take the square root of both sides;

$x-1 = +/- \ \ \sqrt{2} \\\\x = 1 + \sqrt{2} \ \ or \ 1- \sqrt{2}$

Therefore, option B is the right solution.

3 0

2 years ago