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BARSIC [14]
2 years ago
10

Cordell bought new tires for his bicycle. As he rode his bike on the hot street, the temperature of the air in the tires increas

ed. If the volume of the air stayed the same, what happened to the pressure inside the tires?
Chemistry
1 answer:
Wewaii [24]2 years ago
7 0

Answer:

the pressure increased

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Hitman42 [59]

Answer:

An ice pack uses friction and the chemicals inside make it mix to make it cold

Explanation:

3 0
2 years ago
Balance this equation. If a coefficient of "1" is required, choose "blank" for that box. ____CO +____ O2 → ____CO2
Black_prince [1.1K]
<h3><u>Answer;</u></h3>

2, Blank, 2 ;

<h3><u>Explanation;</u></h3>

The balanced chemical equation would be;

2 CO + O2 → 2 CO2

Balancing a chemical equation ensures that the number of atoms of each element are equal on both the reactants side and the products side. This ensures that the law of conservation of mass is obeyed in chemical reactions.

4 0
3 years ago
Read 2 more answers
when 6.25 grams of pure iron are allowed to react with oxygen , a black oxide forms. if the product weighs 8.15 g, what is the e
erik [133]
We are given with the mass of  pure iron that reacts with oxygen to form an oxide which has a given mass as well. the mass of oxygen reacted is 8.15-6.25 g or 1.9 grams. THen we convert the mass of the reactants to moles. Iron is equal to 0.1119 moles and oxygen is equal to 0.1188. We divide each number to the less amount. Hence iron is 1 and oxygen is approx 1. The empirical formula hence is FeO or ferrous oxide or Iron (II) oxide.
5 0
2 years ago
True or False: When you measure something with a ruler, you should NOT estimate an extra digit. You only need to report the numb
sveticcg [70]

Answer:

False

Explanation:

It is important to give exact measurements.

5 0
3 years ago
A 2 L container contains 5 moles of helium gas at 0.5 atm. What is the<br> temperature of the gas?
lara [203]

Answer:

2.44 K IS THE TEMPERATURE OF THE GAS

Explanation:

PV = nRT

P = 0.5 atm

V = 2 L

n = 5 moles

R = 0.082 L atm mol^-1 K^-1

T = ?

Substituting for T in the equation, we obtain:

T = P V / nR

T = 0.5 * 2 / 5 * 0.082

T = 1 / 0.41

T = 2.44 K

The temperature of the gas is 2.44 K

7 0
3 years ago
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