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Len [333]
3 years ago
5

Can anyone solve this?

Chemistry
1 answer:
Sonja [21]3 years ago
4 0

Answer:

3P2O5:

P:6 O:15

5CO2

C:5 O:10

3C6H12O6

C:18 H:36 O:18

4C6H12

C:24 H:48

3Mg3(PO4)2

Mg:9 P:2 O: 8

4(NH4)2S

N:8 H:32 S:4

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A 0.175 M solution of an enantiomerically pure chiral compound D has an observed rotation of +0.27° in a 1-dm sample
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Answer:

The specific rotation of D is 11.60° mL/g dm

Explanation:

Given that:

The path length (l) =  1 dm

Observed rotation (∝) = + 0.27°

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Molar mass = 133.0 g/mol

Concentration in (g/mL) = 0.175 mol/L × 133.0 g/mol

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The specific rotation [∝] = ∝/(1×c)

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= 11.60° mL/g dm

Thus, the specific rotation of D is 11.60° mL/g dm

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