Answer:
Empirical formula = K₂SO₄
The name of the compound is Potassium tetraoxosulfate (vi)
Explanation:
Percentage composition of the elements:
Potassium = 44.82%
Sulfur = 18.39%
Oxygen = 36.79%
Mole ratio of the elements:
Potassium = 44.82/39 =1.15
Sulfur = 18.39/32 = 0.57
Oxygen = 36.79/16 = 2.29
Dividing by the smallest ratio in order to obtain the simplest ratio
Potassium = 1.15/0.57 =2
Sulfur = 0.57/0.57 = 1
Oxygen = 2.29/0.57 = 4
Therefore, the mole ratio of Potassium : Sulfur : Oxygen = 2:1:4
Empirical formula = K₂SO₄
The name of the compound is Potassium tetraoxosulfate (vi)
It would weigh 6.77 kilo i believe
I will say my answer is: Angel
Answer:
K= 25.16%
Mn= 34.59%
O= 40.25%
Explanation:
Find the total mass of the compound. You can do this by multiplying by the molar mass.
add them:
40+55+64=159g
Now convert each element individually to grams using molar mass
Divide by the mass of the compound and multiply by 100
