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Len [333]
3 years ago
5

Write the name of the period that has the digits 913

Mathematics
1 answer:
Elina [12.6K]3 years ago
8 0
Gggggguyttffffdffyuu
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You jog 3 kilometers in 12 minutes.
IgorLugansk [536]
12/3 = 4 minutes
4 minutes per kilometre
4x7=28
28 minutes
6 0
3 years ago
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What is 0.005 in percent and fraction
Sati [7]
For percent, you just move the decimal over two spaces to the right, and add the percent sign. In which that would be:
<em> .5%</em>
And for the fraction: Since the 5 is in the thousandths place, the fraction would equal to:
\frac{5}{1000}     when simplafied:    \frac{1}{200}

~Hope this helped :)

4 0
3 years ago
HELP ASAP GEOMETRY CIRCLES 10TH GRADE
Aleksandr-060686 [28]

Answer:

a): 68

b): 32

Step-by-step explanation:

In a triangle, there is a total of 180 degrees

We are given 2 out of the 3 angles, 54 and 58 degrees

180-54-58= 68 degrees

In the other angle, both lines form a 90-degree angle

We are given 58 degrees, so the rest must be 32.

5 0
3 years ago
The population of bacteria in a culture grows at a rate proportional to the number of bacteria present at time t. After 3 hours
ella [17]

Answer:

137

Step-by-step explanation:

Use the model A = Pe^(kt), where P is the initial number and k is the growth constant.  Then, in case 1,

300 = Pe^(k*3)

and in case 2,

4000 = Pe^(k*10).  We need to find P and e^k.

300 = Pe^(k*3) can be rewritten as (300/P) = [e^k]^3, which in turn may be solved for e^k:

∛(300/P) = e^k

Now we go back to 4000 = Pe^(k*10) and rewrite it as (4000/P) = [e^k]^10.  Substituting ∛(300/P) for e^k, we obtain:              

(4000/P) =  (300/P )^(10/3)

which must now be solved for P.  Raising both sides by the power of 3, we get:

(4000/P)^3 = (300/P)^10.  Therefore,

4000^3       300^10

------------- = -------------

   P^3             P^10

which reduces to:

4000^3       300^10

------------- = -------------

       1             P^7

or

        1         P^7

------------  =  -----------

4000^3       300^10

or:

           300^10

P^7 = ---------------- = 9.226*10^13  = 92.26*10^12

           4000^3

Taking the 7th root of both sides results in P = (92.26*10^12)^(1/7), or

                                                                        P = 137.26

The initial number of bacteria was 137.

7 0
3 years ago
Write a multiplication problem in which the product is between 0.05 and 0.75
Sergio039 [100]
1  multiplied by 0.50 or multiplied by any number between .05 and 0.75
4 0
3 years ago
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