3xc = -5, solve for x
1 answer:
Answer:
Step-by-step explanation:
You want x alone on the left side.
x is being multiplied by 3 and by c.
The opposite operation of multiplication is division. You must divide 3xc by 3c to end up with just x.
You must do the same operation to both sides of an equation, so divide both sides by 3c.
Divide both sides by 3c.
Simplify both sides.
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Hi there!
When we have an equation standard form...
...the formula of the discriminant is
D = b^2 - 4ac
When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions
1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0
Plug in the values from the equation into the formula of the discriminant
D > 0 and therefore we have two real solutions.
2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0
Again, plug in the values from the equation into the formula of the discriminant.
D = 0 and therefore we have one real solution.
~ Hope this helps you.
When we have an equation standard form...
...the formula of the discriminant is
D = b^2 - 4ac
When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions
1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0
Plug in the values from the equation into the formula of the discriminant
D > 0 and therefore we have two real solutions.
2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0
Again, plug in the values from the equation into the formula of the discriminant.
D = 0 and therefore we have one real solution.
~ Hope this helps you.