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Ne4ueva [31]
3 years ago
13

Find the midpoint in geometry.

Mathematics
1 answer:
algol [13]3 years ago
4 0
  • (3,6)
  • (3,-2)

\\ \rm\longmapsto (x,y)=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)

\\ \rm\longmapsto (x,y)=\left(\dfrac{3+3}{2},\dfrac{6-2}{2}\right)

\\ \rm\longmapsto (x,y)=\left(\dfrac{6}{2},\dfrac{4}{2}\right)

\\ \rm\longmapsto (x,y)=(3,2)

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Answer:

<h2>LCD = 9</h2>

Equivalent Fractions with the LCD

1/3 = 3/9

5/9 = 5/9

Solution:

Rewriting input as fractions if necessary:

1/3, 5/9

For the denominators (3, 9) the least common multiple (LCM) is 9.

LCM(3, 9)

Therefore, the least common denominator (LCD) is 9.

Calculations to rewrite the original inputs as equivalent fractions with the LCD:

1/3 = 1/3 × 3/3 = 3/9

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Eight students ran a 180-meter course during their physical education class. The chart shows the time it took each student to co
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Answer:

Step-by-step explanation:

Speed of student 1 = 180/30= 6 m/sec

speed of student 2= 180/32= 5.62 m/sec

speed of student 3= 180/33= 5.45 m/sec

speed of student 4= 180/35= 5.14 m/sec

speed of student 5= 180/37= 4.86 m/sec

speed of student 6= 180/38= 4.73 m/sec

speed of student 7= 180/40= 4.5 m/sec

speed of student 8= 180/32= 4 m/sec

average speed is = (6+5.62+5.45+5.14+4.86+4.73+4.5+4)/8

hence, average speed is= 5.04

hence, the average speed of student 1 = 6m/sec

how much faster is average speed of student 1 than average speed= 6- 5.04 = 0.96

hence, average speed of student 1 is 0.96 m/sec more thanthe average speed.

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Answer:

Step-by-step explanation: R+8

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