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kolezko [41]
3 years ago
12

In a single throw of two coins,find the probability of getting each of the following:-)

Mathematics
1 answer:
oee [108]3 years ago
7 0

Step-by-step explanation:

1.) two tails :

total no. of outcomes possible is TT,TH,HT,HH

no. of outcomes with TT is 1

p( tails on both) = 1/4

2.) tails at least one:

no. of outcomes with one tails atleast is 3 (TT,th,ht,)

p( atelast one tails) = 3/4

3.) tails on one

no. of outcomes with one tails at most is 2 (th,ht)

p( atmost one tails) is 2/4= 1/2

4. no tails

no. of outcomes with no tails is 1(HH)

p( no tails) = 1/4

hope it's understandable.

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What is the ratio of the area of the inner square to the area of the outer square?
Anastasy [175]

Answer:

\frac{(a-b)^2+b^2}{a^2}

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

=\sqrt{(a-b-0)^2+(0-b)^2}

=\sqrt{(a-b)^2+b^2}

Thus the area of the inner square = (side)²

=(\sqrt{(a-b)^2+b^2})^2

=(a-b)^2+b^2\text{ square cm}

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

=\sqrt{(a-0)^2+0^2}

=\sqrt{a^2}=a

Thus, the area of the outer square = (side)²

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Hence, the ratio of the area of the inner square to the area of the outer square

=\frac{(a-b)^2+b^2}{a^2}

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3 years ago
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Step-by-step explanation:

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3 years ago
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Answer:

x = 20

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Step-by-step explanation:

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