PLSSSSSSSSSSASS HELPPPPPPPPPPP MEEEEEEEE OUTTTTT

Can someone please help me with my homework maths please. thanks

mario62 [17]

Answer:

35 blocks are given to the class

Step-by-step explanation:

she has 19 pounds which she divides into 1/2 pounds

19/1/2

38 blocks

she keeps 3 of the blocks and gives the rest away

38-3

35 blocks

4 0

2 years ago

You are baking donuts for your class. There are eight total students in your class and you have to bake 11 donuts. Right and sol

garri49 [273]

Answer:

8+11x

Step-by-step explanation:

5 0

2 years ago

A scrap metal dealer claims that the mean of his sales is "no more than $80," but an Internal Revenue Service agent believes the

Artyom0805 [142]

Answer:

There is enough not evident to support dealer's claim that his sales is no more than $80.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = $80

Sample mean, $\bar{x}$ = $91

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = $21

First, we design the null and the alternate hypothesis

$H_{0}: \mu \leq 80\text{ dollars}\\H_A: \mu > 80\text{ dollard}$

We use one-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{91 - 80}{\frac{21}{\sqrt{20}} } = 2.3425$

Now, $t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = 1.729$

Since,

The calculated test statistic is greater than the critical value, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.

Conclusion:

There is enough not evident to support dealer's claim that his sales is no more than $80.

4 0

3 years ago

The standard deviation of a sample taken from population A is 17.6 for a sample of 25. The standard deviation of a sample taken

Dmitry_Shevchenko [17]

The answer is 5.5

The standard deviation (sd or σ) of the sample mean difference is:
sd = √(sd₁²/n₁ + sd₂²/n₂)

For the population A:
sd₁ = 17.6
n₁ = 25

For the population B:
sd₂ = 21.2
n₂ = 30

Hence:
sd = √(sd₁²/n₁ + sd₂²/n₂)
= √(17.6²/20 + 21.2²/30)
= √(309.76/20 + 449.44/30)
= √(15.49 + 14.98)
= √(30.47)
= 5.5

5 0

3 years ago

During the first 11 months of a recent year, a certain charitable organization received an average (arithmetic mean) of $20,600

Aleks04 [339]

Answer:

D. $25,400

Step-by-step explanation:

Let x represent the score during December.

We have been given that during 1 months of a recent year, a certain charitable organization received an average (arithmetic mean) of $20,600 per month in donations.

The total score for 11 months would be $11\times 20,600=226600$ .