7 dosent go into 4 at all but 4 goes into 7 once
Answer:
16.07 milligrams
Step-by-step explanation:
From the question,
Using the formula of radioactive decay,
R/R' = 2ᵃ/ᵇ..................... Equation 1
Where R = Original mass of the polonium-210, R' = Final mass of polonium-210 after decaying, a = Total disintegration time, b = half life of polonium-210.
Make R' the subject of the equation
R' = R/(2ᵃ/ᵇ)................ Equation 2
Given: R = 100 milligrams, a = 1 years = 365 days, b = 138.39 days
Substitute these values into equation 2
R' = 100/(2³⁶⁵⁰⁰/¹³⁸³⁹)
R' = 100/(6.222)
R' = 16.07 milligrams of plonium-210
which problems? i can teach you how to do them if you want me too.
Answer:
f(2) = 11
Step-by-step explanation:
f(x) = 3x+5
f(2) = 3(2)+5
f(2) = 6+5
f(2) = 11
Ex 1
the number from 1 to 100, I'll call it x
= (((x + 11) * 6 - 3) / 3 + 5) / 2 - x
= ((6x + 66 - 3) / 3 + 5) / 2 - x
= ((6x + 63) / 3 + 5) / 2 - x
= (2x + 21 + 5) / 2 - x
= (2x + 26) / 2 - x
= x + 13 - x
= 13
finally geez
Ex 2
theres 16 teams.
after a team that loses twice they're out.
1 should be left, therefor 15 teams should be out.
15 * 2 = 30,
there should be 30 or 31 games if the last team alive lost 1 game.
