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Elden [556K]
2 years ago
11

What division problem iS being modeled?

Mathematics
1 answer:
Nata [24]2 years ago
7 0

Answer: I THINK fraction

Step-by-step explanation:

1/4 = fraction

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Please help my<br> home work is due tomorrow
bekas [8.4K]
Why is everything due tomorrow xD. Also im sorry but I dont understand this either.
5 0
3 years ago
A human blinks 9,460,800 times per year. A dog blinks 1,861,440 times per year. About how many more times does a human blink tha
Rainbow [258]

Answer:

The answer is D.

Step-by-step explanation:

In order to find how many times human blink more than the blink of a dig, you have to divide it :

9460800 \div 1861440

= 5 \: times

8 0
3 years ago
Read 2 more answers
Which pair of equations can be used to solve for x in PQR?
almond37 [142]

Answer:

A

Step-by-step explanation:

sin57° = \frac{opposite}{hypotenuse} = \frac{PQ}{PR} = \frac{x}{18}

∠ P = 180° - (90 + 57)° ← sum of angles in triangle

∠ P = 180° - 147° = 33° , then

cos33° = \frac{adjacent}{hypotenuse} = \frac{PQ}{PR} = \frac{x}{18}

Thus the 2 ratios used to solve for x are A

7 0
3 years ago
) Set up a double integral for calculating the flux of F=3xi+yj+zk through the part of the surface z=−5x−2y+2 above the triangle
Fynjy0 [20]

The surface (call it S) is a triangle with vertices at the points

x=0,y=0\implies z=2\implies(0,0,2)

x=0,y=2\implies z=-2\implies(0,2,-2)

x=2,y=0\implies z=-8\implies(2,0,-8)

Parameterize S by

\vec s(u,v)=(1-v)(2,0,-8)+v\bigg((1-u)(0,2,-2)+u(0,0,2)\bigg)=(2-2v,2v-2uv,-8+6v+4uv)

with 0\le u\le1 and 0\le v\le1. Take the normal vector to S to be

\vec s_v\times\vec s_u=(20v,8v,4v)

Then the flux of \vec F across S is

\displaystyle\iint_S\vec F(x,y,z)\cdot\mathrm d\vec S=\int_0^1\int_0^1\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_v\times\vec s_u)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^1\int_0^1(6-6v,2v-2uv,-8+6v+4uv)\cdot(20v,8v,4v)\,\mathrm du\,\mathrm dv

=\displaystyle8\int_0^1\int_0^1(11v-10v^2)\,\mathrm du\,\mathrm dv=\boxed{\frac{52}3}

8 0
3 years ago
What is the answer to this equation?
RoseWind [281]
This might be right?

7 0
2 years ago
Read 2 more answers
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