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4 years ago

The top of a hill rises 428 feet above Checkpoint 2 (-189) What is the altitude of the top of the hill?

Mathematics

1 answer:

Eduardwww [97]4 years ago

3 0

Answer:

239 FEET.

Step-by-step explanation:

the altitude of the hill must be subtracted by the depth of the ckeckpoint(2)(-189)

therefore the altitude of the hill comes out to be 428-189=239feet.

therefore,the actual altitude of the hill is 239 feet.

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The function V(S) = 0.094S can be used to find the approximate volume of a sphere (V, in cubic units) in terms of its surface ar

trasher [3.6K]

We have V= 0.094 S.
We also have V = 1930.75 cm^3.
Plug in this value in the formula V= 0.094 S, to get

1930.75 = 0.094 S
>> 1930.75 / 0.094 = S
>> S = 20539.89 cm^2

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3 years ago

A mile is 5,280 feet. Between which to integers is the elevation in miles?

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5300 and 6000 is the elevation in miles

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3 years ago

4^3 x4^5 A.16^8 B.16x15 C.4^15 D.4^8

n200080 [17]

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3 years ago

Read 2 more answers

Solve this system of equations by using substitution 3x + 5y = 23 y= x + 3

Iteru [2.4K]

Answer:

x=1

y=4

(1,4)

Step-by-step explanation:

TO SOLVE FOR X:

1. Substitute y=x+3 into the equation. This should look like this:

3x+5(x+3)=23

2. Use the distributive property.

3x+5x+15=23

3. Simplify:

8x+15=23

4. Subtract 15 from both sides. It should now lool like this:

8x=8

5. Divide both sides by 8.

x=1

TO SOLVE FOR Y:

1. Take x and substitute into original statement:

3(1)+5y=23

2. Simplify:

3+5y=23

3. Subtract 3 from both sides:

5y=20

4: Simplify:

y=4

CHECK ANSWER:

y=x+3

1. Substitute your answers

4=1+3

2. Simplify

4=4

3. Check for Truth. Is 4=4?

Yes. So your final answer is:

x=1

y=4

(1,4)

6 0

4 years ago

Suppose that vehicles taking a particular freeway exit can turn right (R), turn left (L), or go straight (S). Consider observing

Kazeer [188]

Answer:

a. A = {RRR,LLL,SSS}

b. B = {RLS, RSL, LSR, LRS, SRL, SLR}

c. C = {RRS, RRL, RSR, RLR, LRR, SRR}

d. D = {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

e. C U D= {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

C n D = {RRS, RRL, RSR, RLR, LRR, SRR}

Step-by-step explanation:

a..

All three vehicles go in the same direction

This means that all the three vehicles either go straight, or right or left at the same time.

So, A { {RRR, LLL, SSS}

b..

All three vehicles take different directions

Thus means that all the vehicle take different routes

If a vehicle takes the the straight direction, the other 2 vehicles take right and left directions respectively

So, B = {RLS, RSL, LSR, LRS, SRL, SLR}

c..

Exactly two of the three vehicles turn right

This means that two vehicles take right direction while the last vehicle either tske the straight route or left route.

C = {RRS, RRL, RSR, RLR, LRR, SRR}

d..

Exactly two vehicles go in the same direction.

The means that if two vehicles pass straight direction then the third vehicle takes either the right or left direction.

Also, if two vehicles pass right direction, the third vehicle either takes the left direction or straight direction

Lastly, if two vehicles pass left direction then the third vehicle either pass the straight direction or right direction.

D = {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

e. C U D = the union of items in C and D without repetition

So,

C U D= {RRS, RRL, RSR, RLR, LRR, SRR, SSR, SSL, SRS, SLS, LSS, RSS, LLS, LLR, LRL, LSL, SLL, RLL}

C n D = Common items in C and D

C n D = {RRS, RRL, RSR, RLR, LRR, SRR}

List outcomes in D'.D' = List outcomes in C ∪ D.C ∪ D = List outcomes in C ∩ D.C ∩ D =

3 0

3 years ago