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2 years ago

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in the coordinate plane, line m had a slope of 1/4 and a y-intercept of (0,-3). line n is the result of dialating line m by a sc

ale factor of 2 with a center of (0,0). what are the slope and y-intercept of line n?

1 answer:

Verizon [17]2 years ago

4 0

Answer:N/A

Step-by-step explanation:N/A

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Please Explain how you got your answer!

marysya [2.9K]

Answer:

19 miles

Step-by-step explanation:

Let m represent the number of miles traveled. Then the delivery charge is ...

charge = $5.00 + $0.15·m

You want to find the value of m that makes the charge by $7.85, so you want the solution to ...

$7.85 = $5.00 +$0.15·m

$2.85 = $0.15·m . . . . . . . . . subtract $5 (this gives the mileage charge)

$2.85/$0.15 = m = 19 . . . . . divide by the coefficient of m

The number of miles traveled is 19.

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2 years ago

Between 02 30 and 05 15, the same day ,the volume of water in a reservoir increased from 1500 L to 14 700 L. What was the averag

marishachu [46]

Answer:

4,800

Step-by-step explanation:

(14,700- 1,500) / 2 h 45 m

= 13,200 / 2.75

= 4,800 L/h

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2 years ago

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Isabelle drinks orange juice for 36 days in a row. Each day she drinks 2 cups. Which pair of expressions shows two ways to deter

mr_godi [17]

36*2=72, and 2*36=72.

Please mark brainiest!

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2 years ago

What is the answer to this problem

otez555 [7]

3 1/4 = 13/4
2 3/4 = 11/4

13/4 - 11/4 = 2/4 = 1/2

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2 years ago

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A university found that of its students withdraw without completing the introductory statistics course. Assume that students reg

polet [3.4K]

Answer:

A university found that 30% of its students withdraw without completing the introductory statistics course. Assume that 20 students registered for the course.

a. Compute the probability that 2 or fewer will withdraw (to 4 decimals).

= 0.0355

b. Compute the probability that exactly 4 will withdraw (to 4 decimals).

= 0.1304

c. Compute the probability that more than 3 will withdraw (to 4 decimals).

= 0.8929

d. Compute the expected number of withdrawals.

= 6

Step-by-step explanation:

This is a binomial problem and the formula for binomial is:

$P(X = x) = nCx p^{x} q^{n - x}$

a) Compute the probability that 2 or fewer will withdraw

First we need to determine, given 2 students from the 20. Which is the probability of those 2 to withdraw and all others to complete the course. This is given by:

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 2) = 20C2(0.3)^2(0.7)^{18}\\P(X = 2) =190 * 0.09 * 0.001628413597\\P(X = 2) = 0.027845872524$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 1) = 20C1(0.3)^1(0.7)^{19}\\P(X = 1) =20 * 0.3 * 0.001139889518\\P(X = 1) = 0.006839337111$

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 0) = 20C0(0.3)^0(0.7)^{20}\\P(X = 0) =1 * 1 * 0.000797922662\\P(X = 0) = 0.000797922662$

Finally, the probability that 2 or fewer students will withdraw is

$P(X = 2) + P(X = 1) + P(X = 0) \\= 0.027845872524 + 0.006839337111 + 0.000797922662\\= 0.035483132297\\= 0.0355$

b) Compute the probability that exactly 4 will withdraw.

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 4) = 20C4(0.3)^4(0.7)^{16}\\P(X = 4) = 4845 * 0.0081 * 0.003323293056\\P(X = 4) = 0.130420974373\\P(X = 4) = 0.1304$

c) Compute the probability that more than 3 will withdraw

First we will compute the probability that exactly 3 students withdraw, which is given by

$P(X = x) = nCx p^{x} q^{n - x}\\P(X = 3) = 20C3(0.3)^3(0.7)^{17}\\P(X = 3) = 1140 * 0.027 * 0.002326305139\\P(X = 3) = 0.071603672205\\P(X = 3) = 0.0716$

Then, using a) we have that the probability that 3 or fewer students withdraw is 0.0355+0.0716=0.1071. Therefore the probability that more than 3 will withdraw is 1 - 0.1071=0.8929

d) Compute the expected number of withdrawals.

E(X) = 3/10 * 20 = 6

Expected number of withdrawals is the 30% of 20 which is 6.

5 0

3 years ago