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krek1111 [17]
2 years ago
7

Solve If QR = 6x + 1, PR = 14x - 13, and PQ = 5x - 2, find PR

Mathematics
1 answer:
solong [7]2 years ago
7 0

Answer:

P____Q____R

PR= PQ+ QR

(14x-13) = (5x-2)+(6x+1)

14x-13= 11x – 1

14x – 11x = 13–1

3x = 12

x= 12/ 3

x= 4

PR= 14x – 13 = 14 (4) – 13 = 18 – 13= 5

If you want (PQ , QR ) this is the solution

PQ =5x-2=5(4)-2=20-2=18

QR =6x+1=6(4)+1=24+1=25

I hope I helped you^_^

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Answer is A.

√6 + √2
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Read 2 more answers
Cx=r/d<img src="https://tex.z-dn.net/?f=%5Cfrac%7Br%7D%7Bd%7D" id="TexFormula1" title="\frac{r}{d}" alt="\frac{r}{d}" align="abs
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Step-by-step explanation:

ill take the equation as this

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\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b}

Next time when you see someone greif your question, please report it.

Shame for the other guy

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