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Bond [772]
3 years ago
11

What are the uses of hydrogen? ​

Chemistry
2 answers:
Pie3 years ago
7 0
  • Synthesis of ammonia.
  • Manufacturing of nitrogenous fertilizers.
  • Hydrogenation of unsaturated vegetable oils.
  • Manufacturing of organic compounds, for example, methanol.
  • To prepare Hydrogen chloride.
  • Reducing metal oxides to metals by metallurgical processes.
  • Used as rocket fuel.
RoseWind [281]3 years ago
3 0

Nearly all of the hydrogen consumed in the United States is used by industry for refining petroleum, treating metals, producing fertilizer, and processing foods. U.S. petroleum refineries use hydrogen to lower the sulfur content of fuels.

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What is the percentage yield of O2 if 12.3 g of KClO3 (molar mass 123 g) is decomposed to produce 3.2 g of O2 (molar mass 32 g)
My name is Ann [436]

Answer:

The percentage yield of O2 is 66.7%

Explanation:

Reaction for decomposition of potassium chlorate is:

2KClO₃ →  2KCl  +  3O₂

The products are potassium chloride and oxygen.

Let's find out the moles of chlorate.

Mass / Molar mass = Moles

12.3 g / 123 g/mol = 0.1 mol

So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.

Then, 0.1 mol of chlorate may produce (0.1  .3)/ 2 = 0.15 moles

Let's convert the moles of produced oxygen, as to find out the theoretical yield.

0.15 mol . 32 g/ 1mol = 4.8 g

To calculate the percentage yield, the formula is

(Produced Yield / Theoretical yield) . 100 =

(3.2g / 4.8g) . 100 = 66.7 %

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4 years ago
Any two difference between short sightedness and long sightednes​
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Explanation:

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3 years ago
When she introduced CO(g) and Cl2(g) into a 1.00 L evacuated container, so that the initial partial pressure of CO was 1.86 atm
cupoosta [38]

Answer:

Kp is 0.00177

Explanation:

We state the equilibrium:

CO(g) + Cl₂(g)  ⇆  COCl₂(g)

Initially we have these partial pressures

1.86 atm for CO and 1.27 for chlorine.

During the reaction, x pressure has been converted. As we have 0.823 atm as final pressure in the equilibrium for COCl₂, pressure at equilibrium for CO and chlorine will be:

1.86 - x for CO and 1.27 - x for Cl₂.

And x is the pressure generated for the product, because initially we don't have anything from it. So pressure in equilibrium for the reactants will be:

1.86 - 0.823 = 1.037 atm for CO

1.27 - 0.823 = 0.447 atm for Cl₂

Let's make, expression for Kp:

Partial pressure in eq. for  COCl₂ / P. pressure in eq. for CO . P pressure in eq. for Cl₂

Kp = 0.823 / (1.037 .  0.447) → 0.00177

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3 years ago
Look at the two diagrams below. Diagram 1 shows the locations of earthquakes and diagram 2 shows the locations of volcanoes arou
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Answer:

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Writing Wrap Up. A student says that “ALL DNA codes for proteins.” Do you think this is true? Include in your answer evidence fr
Ymorist [56]

Not all DNA codes for proteins

Explanation:

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