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3 years ago

Which one of the following is a perfect square A: 100, B:13, C:127, or D:102

Mathematics

2 answers:

Tom [10]3 years ago

5 0

A: 100 because a perfect square is just a number squared and 10 squared is 100 :)

nirvana33 [79]3 years ago

5 0

Which of the following is a perfect square?
 A. 100

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What is the slope between (-4,4) and (-6,6)

nalin [4]

$\textsf{Let's calculate the slope of the line passing thought the points (-4, 4) and (-6, 6) } \\ \textsf{using the following formula: }\mathsf{m = \frac{\Delta y}{\Delta x}} \textsf{ where m is the slope of the line.}$ $\textsf{So:}$

$\mathsf{m = \dfrac{\Delta y}{\Delta x} = \dfrac{4 - 6}{-4 - (-6)} = \dfrac{-2}{2} = -1}$

$\textsf{Hence the slope is -1.}$

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4 years ago

If f(x) = x2 – 3, then f(-1) is equivalent to

zloy xaker [14]

Answer:

negative 5. or -5

Step-by-step explanation:

f(-1)= (-1)2-3

2 times -1= -2

-2-3= -5

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3 years ago

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slava [35]

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3 years ago

compute the projection of → a onto → b and the vector component of → a orthogonal to → b . give exact answers.

Nina [5.8K]

$\text { Saclar projection } \frac{1}{\sqrt{3}} \text { and Vector projection } \frac{1}{3}(\hat{i}+\hat{j}+\hat{k})$

We have been given two vectors $\vec{a}$ and $\vec{b}$ , we are to find out the scalar and vector projection of $\vec{b}$ onto $\vec{a}$

we have $\vec{a}=\hat{i}+\hat{j}+\hat{k}$ and $\vec{b}=\hat{i}-\hat{j}+\hat{k}$

The scalar projection of $\vec{b}$ onto $\vec{a}$ means the magnitude of the resolved component of $\vec{b}$ the direction of $\vec{a}$ and is given by

The scalar projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|}$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\sqrt{1^2+1^1+1^2}} \\&=\frac{1^2-1^2+1^2}{\sqrt{3}}=\frac{1}{\sqrt{3}}\end{aligned}$

The Vector projection of $\vec{b}$ onto $\vec{a}$ means the resolved component of $\vec{b}$ in the direction of $\vec{a}$ and is given by

The vector projection of $\vec{b}$ onto

$\vec{a}=\frac{\vec{b} \cdot \vec{a}}{|\vec{a}|^2} \cdot(\hat{i}+\hat{j}+\hat{k})$

$\begin{aligned}&=\frac{(\hat{i}+\hat{j}+\hat{k}) \cdot(\hat{i}-\hat{j}+\hat{k})}{\left(\sqrt{1^2+1^1+1^2}\right)^2} \cdot(\hat{i}+\hat{j}+\hat{k}) \\&=\frac{1^2-1^2+1^2}{3} \cdot(\hat{i}+\hat{j}+\hat{k})=\frac{1}{3}(\hat{i}+\hat{j}+\hat{k})\end{aligned}$

To learn more about scalar and vector projection visit:brainly.com/question/21925479

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3 0

1 year ago

Jocelyn gave the cashier $50 to pay for 3 shirts. The cashier gave her $5.03 in change. Each shirt cost the same amount. W

Goryan [66]

Answer:

14.9

Step-by-step explanation:

50-5.03 = 44.97

44.97 ÷ 3 = 14.99

8 0

2 years ago