Answer:convergent
Step-by-step explanation:
Given
Improper Integral I is given as


integration of
is 
![I=1000\times \left [ e^x\right ]^{0}_{-\infty}](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20%5Cleft%20%5B%20e%5Ex%5Cright%20%5D%5E%7B0%7D_%7B-%5Cinfty%7D)
![I=1000\times I=\left [ e^0-e^{-\infty}\right ]](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20I%3D%5Cleft%20%5B%20e%5E0-e%5E%7B-%5Cinfty%7D%5Cright%20%5D)
![I=1000\times \left [ e^0-\frac{1}{e^{\infty}}\right ]](https://tex.z-dn.net/?f=I%3D1000%5Ctimes%20%5Cleft%20%5B%20e%5E0-%5Cfrac%7B1%7D%7Be%5E%7B%5Cinfty%7D%7D%5Cright%20%5D)

so the integration converges to 1000 units
Answer:
the answer is i think is 60.7
Okay so I did the problem and they tricked us. That minus sign you see next to the x48 is actually a negative sign so you actually are suppose to divide to get 1.3 and I believe that's the answer.
X=1
x2= 1.3
Answer:

Step-by-step explanation:
Given: Let A be the event that the first die lands on 2 and B be the event that the second die lands on 2.
To find:
P(A), the probability that the first die lands on 2
P(B), the probability that the second die lands on 2
P(A and B): the probability that the first die lands on 2 and the second die lands on 2
Solution:
Probability refers to chances of occurrence of some event.
Probability = number of favourable outcomes/total number of outcomes
Sample space = 
Total number of outcomes = 6
For P(A):
Number of favourable outcomes = 1
So,

For P(B):
Number of favourable outcomes = 1
So,

P(A and B) = 
Yes, A and B are independent events as happening of each of the event does not depend on the other.