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Sladkaya [172]
3 years ago
5

Question 13 (2 points)

Mathematics
1 answer:
Eddi Din [679]3 years ago
4 0

Answer:

The math club has 22 students, and the art club has 34 students.

Step-by-step explanation:

Given that there are a total of 56 students between the art club and the math club, and that the art club has 12 more students than the math club, to determine how many students there are in each club, the following calculation must be performed:

X + X + 12 = 56

2X + 12 = 56

2X = 56 - 12

X = 44/2

X = 22

Thus, the math club has 22 students, and the art club has 34 students.

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Determine whether the improper integral converges or diverges, and find the value of each that converges.
shusha [124]

Answer:convergent

Step-by-step explanation:

Given

Improper Integral I is given as

I=\int_{-\infty}^{0}1000e^xdx

I=1000=\int_{-\infty}^{0}e^xdx

integration of e^x is e^x

I=1000\times \left [ e^x\right ]^{0}_{-\infty}

I=1000\times I=\left [ e^0-e^{-\infty}\right ]

I=1000\times \left [ e^0-\frac{1}{e^{\infty}}\right ]

I=1000\times 1=1000

so the integration converges to 1000 units  

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3 years ago
I’ll give you brainlest if you answer this correctly
BaLLatris [955]
No give it to now lol
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Answer:

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3 years ago
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Suppose that Ayumi rolls a pair of fair six-sided dice. Let A be the event that the first die lands on 2 and B be the event that
Tanya [424]

Answer:

\frac{1}{6} ,\frac{1}{6} ,\frac{1}{36}\,,\,independent

Step-by-step explanation:

Given: Let A be the event that the first die lands on 2 and B be the event that the second die lands on 2.

To find:

P(A), the probability that the first die lands on 2

P(B), the probability that the second die lands on 2

P(A and B): the probability that the first die lands on 2 and the second die lands on 2

Solution:

Probability refers to chances of occurrence of some event.

Probability = number of favourable outcomes/total number of outcomes

Sample space = \left \{ 1,2,3,4,5,6 \right \}

Total number of outcomes = 6

For P(A):

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So,

P(A)=\frac{1}{6}

For P(B):

Number of favourable outcomes = 1

So,

P(B)=\frac{1}{6}

P(A and B) = P(A)P(B)=\left ( \frac{1}{6} \right )\left ( \frac{1}{6} \right )=\frac{1}{36}

Yes, A and B are independent events as happening of each of the event does not depend on the other.

5 0
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