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marin [14]
3 years ago
5

Calculate the number of moles in 2.5 particle NaOH​

Chemistry
1 answer:
andreev551 [17]3 years ago
7 0

Answer:

1.5055×10²⁴

Explanation:

................................

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Pleasee help ASAP<br> will mark brainliest!
Anastasy [175]

Answer:

question 1- is B

question 2- is A

*I hope this helps you guys out!

7 0
3 years ago
Consider the equation below. CaCO3(s) &lt;—&gt;CaO(s) + CO2(g) what is the equilibrium constant expression for the given reactio
hichkok12 [17]

Answer:

Answer is: Keq = [CO₂].

Explanation:

Balanced chemical reaction: CaCO3(s) ⇄ CaO(s) + CO₂(g).

The equilibrium constant (Keq) is a ratio of the concentration of the products  to the concentration of the reactants.

Pure liquids (shown in chemical reactions by appending (l) to the chemical formula) and solids (shown in chemical equations by appending (s) to the chemical formula) not go in to he equilibrium constant expression, only gas state (shown in chemical reactions by appending (g) to the chemical formula) reactants and products go in to  the equilibrium constant expression

8 0
3 years ago
Read 2 more answers
True or False: Mutually beneficial relationships, predator-prey relationships, and competition can happen in different environme
Masja [62]

Answer:

Yes :)

Explanation:

Mutual relationships can include birds cleaning out aligators' teeth, which helps with their hygiene, and gives the bird a meal!

Predator-prey would be a cheetah-antelope.

Competition could be an invasive species :)

8 0
2 years ago
Use the following information to calculate the concentration, Ka and pka for an unknown monoprotic weak acid. (8 pts.) 20.00 mL
lisov135 [29]

Answer:

Concentration: 0.185M HX

Ka = 9.836x10⁻⁶

pKa = 5.01

Explanation:

A weak acid, HX, reacts with NaOH as follows:

HX + NaOH → NaX + H2O

<em>Where 1 mole of HX reacts with 1 mole of NaOH</em>

To solve this question we need to find the moles of NaOH at equivalence point (Were moles HX = Moles NaOH).

18.50mL = 0.01850L * (0.20mol / L) = 0.00370 moles NaOH = Moles HX

In 20.0mL = 0.0200L =

0.00370 moles HX / 0.0200L = 0.185M HX

The equilibrium of HX is:

HX(aq) ⇄ H⁺(aq) + X⁻(aq)

And Ka is defined as:

Ka = [H⁺] [X⁻] / [HX]

<em>Where [H⁺] = [X⁻] because comes from the same equilibrium</em>

As pH = 2.87, [H+] = 10^-pH = 1.349x10⁻³M

Replacing:

Ka = [H⁺] [H⁺] / [HX]

Ka = [1.349x10⁻³M]² / [0.185M]

Ka = 9.836x10⁻⁶

pKa = -log Ka

<h3>pKa = 5.01</h3>
6 0
3 years ago
Complete the table for ion charge based upon their losing or gaining electrons in the outer shell. (Use the periodic table as ne
PolarNik [594]

Answer:

Explanation:

Group one:

The elements of group one shows +1 charge because these all are metals and lose their one valance electron.

Hydrogen lithium sodium potassium rubidium cesium francium

Group 2:

The elements of group two shows +2 charge because these all alkali metals and lose their two valance electrons.

beryllium magnesium calcium strontium barium radium

Group 3:

The elements of group three-B shoes +3 charge by losing three valance electrons.

Scandium yttrium lanthanum actinium

Group 4:

The elements of group 4th A and 4th B lose four electrons or gain four electrons to complete the octet and shows +4 or -4 charge.

Group 5:

Group 5th elements gain three electrons and shows -3 charge to complete the 8 electrons. (octet).

It involve the elements of group 5th A.

Group 6:

The elements of group 6A gain two electrons to complete the octet and shows -2 charge.

Group 7:

The elements of group 7A gain one electron to complete the octet and shows -1 charge.

Group 8:

The elements of group 8A are noble gases and have complete octet. That's why shows 0 charge.

4 0
3 years ago
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